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2 years ago

I NEED HELP SOLVING THIS MATH PROBLEM.

Mathematics

1 answer:

olasank [31]2 years ago

3 0

Answer:

19s

Step-by-step explanation:

s = 1s

1s+8s+10s=（1+8+10）s=19s

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Carlton is using the following data samples to make a claim about the house values in his neighborhood:

olga2289 [7]

The answer is A because there is a outlier which is $100,000

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3 years ago

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

What is the square root of -1?<br> -j.<br> -1

Sindrei [870]

Answer:

Its not a real number for the square roots of negative number

its not possible... $\sqrt{-4}$ = -2 x -2 no... 2 x 2 no..... -2 x 2 yea but thats not square root anymore...

Step-by-step explanation:

Give me brainliest!!!

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3 years ago

What is a quadrilateral with four congruent sides

Verdich [7]

That's a <em>rhombus</em>. If it has one interior right angle, then
it's a special case of rhombus known as a "square".

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3 years ago

Find the length of the third side to the nearest tenth 6 and 9

oee [108]

Hello, i do believe that you are asking me to do pythagorean theorem.

I'm not too sure if we are solving hypotenuse or a/b so i'll do both.

$\boxed{\underline{Hypotenuse...}}\\\\\\A^2+B^2=C^2\\6^2+9^2=C^2\;\\36+81=117$

$\sqrt{117}=10.816\\Round-\;10.8$

$\boxed{\underline{a/b...}}\\\\\\A^2=C^2-B^2\\A^2=9^2-6^2\\A^2=81-36\\A^2=45\\\sqrt{45}= 6.708\\Round-\;6.7$

Hope it helps!

6 0

3 years ago