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3 years ago

Use the figure to answer the question that follows:

Mathematics

1 answer:

Olegator [25]3 years ago

3 0

Answer:

m∠SQV + m∠VQT = 180°

Step-by-step explanation:

m∠SQT is substituted by 180° at step 5

4 m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
5 m∠SQV + m∠VQT = 180° Substitution Property of Equality
6 m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem

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Solve for m. m/9 +16 <17

-Dominant- [34]

Any negative number

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2 years ago

ana wants to earn 88 percent in her chemistry class she has one quiz left to take on the first 5 quizzes she received a 74 perce

Alinara [238K]

Answer: 91

Step-by-step explanation: I assume you had a typo and mean what did Ana need on the 5th quiz since you only listed 4 quiz scores.

(74 + 92 + 83 + 100 + x)/5 = 88

(349 + x)/5 = 88

((349 +x)/5) x 5 = 88 x 5

349 + x = 440

x = 440-349

x = 91

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3 years ago

A line with a slope of -7 passes through the points (u,0) and (8,-7) what is the value of u?

laila [671]

Answer:

u = 7

Step-by-step explanation:

Using the slope intercept formula:

$\frac{y2 - y1}{x2 - x1} = slope$

Substitute our values from the points and the known slope:

$\frac{-7 - 0}{8 - u} = -7$

Now we multiply both sides by (8 - u) to isolate the x:

(8-u) x $\frac{-7}{8 - u}$ = -7 (8 - u)

Next we add 56 to both sides:

-7 = -56 + 7u

Finish off by dividing both sides by 7:

7u = 49

u = 7

6 0

3 years ago

A devastating freeze in California's Central Valley in January 2007 wiped out approximately 75% of the state's citrus crop. It t

solniwko [45]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

The linear equation of the function is: $g(P) = 22.9P+7$ .
The inverse function is: $g^{-1}(c) = \frac{1}{22.9}(c - 7)$ .
A practical domain is from 0% to 100%
A practical range is from 7 to 29.9

A. Input quantity

The input quantity is the percentage of frozen citrus crop

B. Output quantity

The output quantity is the cost of box of oranges

C. The linear function

We have:

$(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)$

Calculate the slope of the function

$m = \frac{c_2 - c_1}{P_2 - P_1}$

$m = \frac{25.32 - 11.58}{80\%-20\%}$

$m = \frac{13.74}{60\%}$

$m = 22.9$

The linear equation is calculated as follows:

$c -c_1 = m(P-P_1)$

$c -11.58= 22.9(P-20\%)$

$c-11.58 = 22.9P-4.58$

D. Rewrite as y = mx + b

We have:

$c-11.58 = 22.9P-4.58$

Collect like terms

$c = 22.9P - 4.58 + 11.58$

$c = 22.9P+7$

The function is:

$g(P) = 22.9P+7$

E. A practical domain

The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: $[0\%,100\%]$

F. A practical range

When P = 0%

$c = 22.9 \times 0\% + 7 = 7$

When P = 100%

$c = 22.9 \times 100\% + 7 = 29.9$

Hence, the range of the function is: $[7,29.9]$

G. The meaning of $g^{-1}(12)$

The inverse function of g(P) is $g^{-1}(P)$

So:

$g^{-1}(12)$ is the percentage of frozen citrus crop, when the cost is $12.

H. The inverse formula

We have:

$c = 22.9P+7$

Subtract 7 from both sides

$c - 7 = 22.9P$

Make P the subject

$P = \frac{1}{22.9}(c - 7)$

So, the inverse formula is:

$g^{-1}(c) = \frac{1}{22.9}(c - 7)$

Substitute 12 for c

$g^{-1}(12) = \frac{1}{22.9}(12 - 7)$

$g^{-1}(12) = \frac{1}{22.9} \times 5$

$g^{-1}(12) = 22\%$

Read more about linear equations at:

brainly.com/question/19770987

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2 years ago

How do you determine if two triangles are similar?

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Side angle side, angle angle angle, ot angle side angle

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