Look at it on the Internet
Answer:
The median of a data set is better when you have a term or terms that are not close to the other terms
Step-by-step explanation:
For example:
Say you have the data set
1, 15, 17, 18, 22, 84
The median of these terms would be 17.5
(it is the exact center of the data group)
17 + 18 = 35
35/2 = 17.5
The mean of these terms would be 26.17
(this number is not close to the center because the numbers 1 and 84
are not close enough to the other terms)
1 + 15 + 17 + 18 + 22 + 84 = 157
157/6 = 26.17
Let's solve this system of equations through substitution.
We have these two equations.
-7x-2y=14
6x+6y=18
Now let divide the second equation by 6.
6x+6y=18 ----> x+y=3
Next, let us move y to the right side of the equation.
x+y=3 -------> x=3-y (x equals 3-y)
Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.
-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)
We have a one variable equation now and can solve for y.
-7(3-y)-2y=14
-21+7y-2y=14
5y=35
y=7
Plug in 7 for y in any equation to find x.
x+y=3
x+7=3
x=-4
answer: x=-4, y=7
Answer:
Choose a point with a negative x coordinate and a positive y coordinate.
Step-by-step explanation:
The quadrants are labeled counter clockwise 1, 2, 3, and 4.
Quadrant I - has x and y coordinate both positive.
Quadrant 2 - has x coordinate negative and y coordinates positive.
Quadrant 3 - has x and y coordinates both negative.
Quadrant 4 - has x coordinates positive and y coordinates negative.
Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).
Answer:
I second that,
Step-by-step explanation: