Answer:
We need 79.6grams of H2SO4
Explanation:
Step 1: data given
Mass of aluminium = 14.6 grams
Molar mass aluminium = 26.98 g/mol
Molar mass H2SO4 = 98.08 g/mol
Step 2: The balanced equation
2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g)
Step 3: Calculate moles Aluminium
Moles Aluminium = mass aluminium / molar mass aluminium
Moles aluminium = 14.6 grams / 26.98 g/mol
Moles aluminium = 0.541 moles
Step 4: Calculate moles H2SO4 need
For 2 moles Al we need 3 moles H2SO4
For 0.541 moles Al we need 3/2 * 0.541 = 0.8115 moles H2SO4
Step 5: Calculate mass H2SO4
Mass H2SO4 = 0.8115 moles * 98.08 g/mol
Mass H2SO4 = 79.6 grams
We need 79.6grams of H2SO4