Based on science 4) 1) 0.25M
2) 0.66M
3) 1.5M
4) 4.0M ––> Therefore, this is the most concentrated
5) 30g NaOH(1 mol NaOH / 40gNaOH) = 0.75 mol NaOH / 0.500L = 1.5M NaOH (3)
6) 1) 1.0 mol / L(1 L) = 1 mol H2SO4
2) 1 mol / L (2 L) = 2 mol H2SO4
3) 0.50 mol / L ( 1.0L) = 0.50 mol H2SO4 ––>
7) 0.200 mol / L (1 L)(74.6g / mol) = 14.92g (2)
8) 0.25 mol / 0.250 L = 1 mol / L = 1M (1)
This is the answer : 1m
Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
Answer:
14.89 g
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
The heat released by the water when it cools down by a temperature difference AT
is Q = mC,AT
where
m=432 g is the mass of the water
C, = 4.18J/gºC
is the specific heat capacity of water
AT = 71°C -18°C = 530
is the decrease of temperature of the water
Plugging the numbers into the equation, we find
Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J
and this is the amount of heat released by the water.
The formula of the ppt. formed is PbSo4 , which is inslouble.
