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Verizon [17]
3 years ago
12

5x-3=21-x please someone answer ​

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
6 0

Answer:

X=4

Step-by-step explanation:

  1. The first thing you would do is to make it so there is only x's on one side. To do this add the x on both sides
  2. This would make it so you have 6x-3=21
  3. Plus the 3 on both sides
  4. This would give you 6x=24
  5. Do 24÷6 giving you 4
  6. X=4
wolverine [178]3 years ago
5 0

Answer:

X=4 Hope it helps Lol

Step-by-step explanation:

  5*x-3-(21-x)=0

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  6x - 24  =   6 • (x - 4)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    6   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    x-4 = 0

Add  4  to both sides of the equation :

                     x = 4

One solution was found :

                  x = 4

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The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.
shusha [124]

Answer:

The graph shows that when x =3 both

\frac{1}{3}x + 1

and 5 – x equal 2

Step-by-step explanation:

The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.

From the graph, the two lines representing the two equations intersect at (3,2).

This implies that the solution to the system

y =  \frac{1}{3} x + 1

and

y=5-x

is x=3, y=2

Hence the value of the two functions equals 2 at x=3.

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How much does gas cost?
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What is the answer for x-5/9= -4?
amid [387]

Answer:

-31/9

Step-by-step explanation:

Bring -5/9 to other side

-4 is also written as -3 9/9

-3 9/9 + 5/9 = x

-3 4/9 = x

5 0
3 years ago
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defon
It’s $1.15 per attempt
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3 years ago
Pls help only if yk it ill give brainliest to the correct answer !
IgorC [24]

Answer:

x=-0.3

x=-11.7

Step-by-step explanation:

4x^2+24x+13=2x^2+6\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\4x^2+24x+13-6=2x^2+6-6\\Simplify\\4x^2+24x+7=2x^2\\\mathrm{Subtract\:}2x^2\mathrm{\:from\:both\:sides}\\4x^2+24x+7-2x^2=2x^2-2x^2\\Simplify\\2x^2+24x+7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=24,\:c=7:\quad x_{1,\:2}=\frac{-24\pm \sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}\\x=\frac{-24+\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad \frac{-12+\sqrt{130}}{2}\\x=\frac{-24-\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad -\frac{12+\sqrt{130}}{2}\\The\:solutions\:to\:the\:quadratic\:equation\:are:\\x=\frac{-12+\sqrt{130}}{2},\:x=-\frac{12+\sqrt{130}}{2}\\\\quad x=-0.29912\ ,\:x=-11.70087

6 0
3 years ago
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