Answer:
5.2
Step-by-step explanation:
a^2+b^2=c^2
Where c is the length of hypotenuse
and a, b are lengths of the legs.
Put in 6 for c,
Put in 3 for a and you get 9+b^2=36
Subtract 9 from both sides and get b^2= 27
Then find the square root of both sides to get b, so the answer is the square root of 27.
The cloest square root is 5, then apporixmate the tenths value and see if they work.
Answer: 5.2
First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
Answer:
4x + 1 and 6x - 2x - 2 + 3
Step-by-step explanation:
we can expand and find 2 equations that are the same as this
one being 6x+3 -2x -2
and another being 4x + 1
hope this helps!
