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user100 [1]
3 years ago
9

Plz help me with this G(x) F(x)

Mathematics
2 answers:
Ann [662]3 years ago
8 0

Answer:

The domains are the same expect for the point x = -3 where f(x) is undefined.

Step-by-step explanation:

Tatiana [17]3 years ago
6 0

Answer: f(x) D: x > -3

              g(x) D: x ≥ -3

<u>Step-by-step explanation:</u>

Graph: f(x) has an asymptote at x = -3, so the domain is: x > -3

Equation: g(x) = √(x + 3)  + 1   has a domain of x + 3 ≥ 0  --> x ≥ -3

<em>I am not sure what the dropbox options are so I will provide 2 possible answers:</em>

The domain of the function<u> f(x) </u>is greater than the domain of the function <u>g(x)</u>

                                                  or

The domain of the function<u> g(x) </u>is less than the domain of the function <u>f(x)</u>

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10th term of an= 20-2n
Dmitry [639]

Answer:

We have that a_{n} = 20-2n

Step-by-step explanation:

We have just to replace n=10 on the general equation

a_{10} = 20-2×10

Therefore:

a_{10} = 0

8 0
3 years ago
Need help please. I don't know
Natali [406]
f(3)=3+1=4
6 0
3 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
If the line you graph is exactly the same as the first one, how many solutions do you
Aleks04 [339]
I think it’s infinitely many
5 0
3 years ago
Antonius the chef wants to cook several batches of lasagna and spaghetti for his restaurant. He plans to use at least 4.54.5 kil
yaroslaw [1]

Answer: No he does not meet both of his expectation by cooking 10 batches of spaghetti and 4 batches of lasagna.

Step-by-step explanation:

Since here S represents the number of batches of spaghetti and L represents the total number of lasagna.

And,  the chef planed to use at least 4.5 kilograms of pasta and more than 6.3 liters of sauce to cook spaghetti and lasagna.

Which is shown by the below inequality,

0.3S+0.65L \geq 4.5 ----------(1)

And,  0.25S+0.8L >6.3 --------(2)

By putting S = 10 and L = 4 in the  inequality (1),

0.3\times 10+0.65\times 4 \geq 4.5

⇒ 5.6\geq 4.5(true)

Thus, for the values  S = 10 and L = 4 the inequality (1) is followed.

Again By putting S = 10 and L = 4 in the  inequality (2),

0.25\times 10+0.8\times 4 >6.3

⇒ 5.7>6.3( false)

But, for the values  S = 10 and L = 4 the inequality (2) is not  followed.

Therefore, Antonius does not meet both of his expectations by cooking 10 batches of spaghetti and 4 batches of lasagna.



4 0
3 years ago
Read 2 more answers
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