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3 years ago

Which measure of center would you use to compare the population represented by the box plots?

Mathematics

2 answers:

kondaur [170]3 years ago

7 0

Answer:

Median

IQR

Step-by-step explanation:

The only average that can be obtained from a box plot is the median.

Also, the measure of dispersion/variability about the median is the interquartile range (IQR)

Elina [12.6K]3 years ago

5 0

Answer:

Median

Step-by-step explanation:

The centers of variation are mean and median. Look at the type of data sets we have to determine which one will best fit the needs here.

Box-and-whisker plots do not provide information about the medians. Instead, the middle line in the boxes are actually the medians. Thus, the answer is median.

Hope this helps!

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20of%20%5C%3A%20rs1" id="TexFormula1" title=" \frac{3}{4} of \: rs1"

Lady_Fox [76]

Answer:

75 paise

Step-by-step explanation:

We know that 1 rs = 100 paise

So, solving the expression gives -

$\frac{3}{4} \times 100 = 3 \times 25 = 75 \: paise$

3 0

3 years ago

Help me with this plsss

worty [1.4K]

I’m trying to get points ignore this, sorry i didn’t know how to help :(!

4 0

3 years ago

Arrange from least to greatest.<br> 5/6 2/4 5/12

Jet001 [13]

Answer:

5/6=10/12. 2/4=6/12. 5/12

5/12. 2/4. 5/6

6 0

3 years ago

If x is an acute angle and tan x = 5,

lyudmila [28]

We have that
tan x=5

we know that
tan x =sin x/ cos x
sin x/ cos x=5------> squaring-----> sin² x/cos² x=25
remember that
sin² x+cos² x=1-----> cos² x=1-sin² x
substitute
sin² x/[1-sin² x]=25
sin² x=25-25*sin² x
26*sin² x=25
sin² x=25/26
sin x=5/√26

cos² x=1-(5/√26)²----> 1-(25/26)----> 1/26
cos x=1/√26

the answers are
sin x=5/√26
cos x=1/√26

4 0

3 years ago

Find the length side of the rectangle <br> cm<br> 5.6 cm<br> A= 62.72 sq cm

olga nikolaevna [1]

Answer:

11.2 cm

Step-by-step explanation:

62.72 / 5.6 = 11.2

6 0

3 years ago