Answer:
B:3(x-1)+2x=3(x-1)+2
Step-by-step explanation:
Aanya wrote the four equations that are shown below.
We need to check each equation and see which equations have same coefficient of x terms on both sides of equation.
A: 6x-8=4(x-2)+2x
Distribute 4 inside the parenthesis
6x-8=4x- 8+2x
We know 4x + 2x is 6x. So, both sides we have 6x. Hence no solution for this equation.
B:3(x-1)+2x=3(x-1)+2
Distribute 3 inside the parenthesis
3x - 3 + 2x = 3x - 3 + 2
5x - 3 = 3x- 3 + 2
Coefficient of x are not same on both sides. So this equation has exactly one solution.
C:7x+2-x=6(x+2)
Distribute 6 inside the parenthesis
6x + 2= 6x + 12
Both sides we have 6x. Hence no solution for this equation.
D:4(x+3)+x=5(x+1)+7
Distribute 4 and 5 inside the parenthesis
5x + 12= 5x + 5+ 12
Both sides we have 5x. Hence no solution for this equation.
Given:
The equation is
To find:
The solution of given equation.
Solution:
We have,
Using distributive property, we get
Adding 7 on both sides, we get
Divide both sides by 4.
Therefore, the value of x is 6.
As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
Y=2 yes (the slope is 0 and the y intercept is 2)
15x + 4 would be the algebraic expression
