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PilotLPTM [1.2K]
4 years ago
6

I can’t figure out what it is asking. How do you find where each line crosses the y-axis?..

Mathematics
1 answer:
frez [133]4 years ago
3 0
The y axis is the vertical line
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How do I solve 1/2 : 3/4
kogti [31]
The answer is two is to three
first see the common multiple of 2&4which is 4 so in end u end up with 2/4 & 3/4 hence answer is 2:3
^ ^
8 0
4 years ago
Solve for v.<br> JE<br> -13=4(v+2) –7v<br> Simplify your answer as much as possible.
Ugo [173]

Step-by-step explanation:

-13=4v+8-7v

-13-8=-3v

3v=21

v=7

8 0
3 years ago
The equation of a line is x + 5y = 12.
Svet_ta [14]

Answer: C: 12/5

Step-by-step explanation:

y intercept is where x is 0, so set x equal to 0

0+5y=12

y=12/5

4 0
3 years ago
How to do this step by step?
serg [7]
The answer is 27.6
angle version of the law of cosines:

cos(C) = (a^2 + b^2 − c^2)/2ab 

cos(A) = (b^2 + c^2 − a^2)/2bc

cos(B) = (c^2 + a^2 − b^2)/2ca


cos A = (b^2 + c^2 − a^2) / 2bc
cos A = (10^2+20^2-14<span>^2)/200
cos A = (100+400-196)/200
cos A = (500-196)/200
cos A = (304)/200
cos A = (1.52)
A = cos</span><span>^-1(1.52) = 40.54 degrees

cos B = (c</span>^2+a^2-b<span>^2)/2ca
cos B = (20</span>^2+14^2-10<span>^2)/280
cos B = (400+196-100)/280
cos B = (496)/280
cos B </span>≈ 1.77
B = cos<span>^-1(1.77) = 27.66 degrees

we have two methods left to find the measure of angle C:
method 1 :
cos C = (a</span>^2+b^2-c<span>^2)/2ab
cos C = (14</span>^2+10^2-20<span>^2)/140
cos C = (196+100-400)/140
cos C = (-104)/140
cos C </span>≈ -0.74

C = cos<span>^-1(-0.74) = 111.8 degrees

method 2: 40.54+27.66 = 68.2
180-68.2=111.8

The measure of angle A: 40.54
The measure of angle B: 27.66
The measure of angle C: 111.8



</span>
6 0
4 years ago
Stacy is selling tickets for the school play. She has a total of 200 seats available, and there will be two types of tickets off
Ganezh [65]

She sold 74 child tickets and 126 adult tickets

Step-by-step explanation:

Stacy is selling tickets for the school play

  • She has a total of 200 seats available, and there will be two types of tickets offered, child and adult tickets
  • She sold each child ticket for $6 , each adult ticket for $10 , and made a total of $1704

We need to find how many of each ticket  she sold

Assume that x is the number of child tickets and y is the number of the adult tickets

∵ She has a total of 200 seats available

∵ She sold x child tickets

∵ She sold y adult tickets

- Add x and y, then equate the sum by 200

∴ x + y = 200 ⇒ (1)

∵ She sold each child ticket for $6

∵ She sold each adult ticket for $10

∵ She made a total of $1704

- Multiply x by 6 and y by 10, then add the products and

   equate them by 1704

∴ 6x + 10y = 1704 ⇒ (2)

Now we have a system of equation to solve it

Multiply equation (1) by -10 to eliminate y

∵ -10x - 10y = -2000 ⇒ (3)

- Add equations (2) and (3) to find x

∴ -4x = -296

- Divide both sides by -4

∴ x = 74

- Substitute the value of x in equation (1) to find y

∵ 74 + y = 200

- Subtract 74 from both sides

∴ y = 126

She sold 74 child tickets and 126 adult tickets

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

6 0
4 years ago
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