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ICE Princess25 [194]
3 years ago
15

Use substitution {y-4x=-7 5x+y=-6

Mathematics
2 answers:
Ainat [17]3 years ago
6 0

Answer:

First, you put the answer in slope intercept form,y=-7+4x. You substiuite which is going to be y-4x+4x=-7+4x. You simplify to y=-7+4x. You plug that into the other equation and solve. It turns out to be y= -59/9, and x=1/9. Hope this helps!

Maksim231197 [3]3 years ago
5 0

Answer:

y - 4x = -7 ...... 1

5x+y=-6 ......... 2

Make y the subject in equation 1

Thus

y = - 7 + 4x

Substitute this into Equation 2

We get

5x - 7 + 4x = - 6

9x = -6 + 7

9x = 1

x = 1/9

Substitute x = 1/9 into equation 1

y = -7 + 4x

y = - 7 + 4(1/9)

y = -7 + 4/9

y = - 59/9

x = 1/9 , y = -59/9

Hope this helps

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jeka94

Answer:

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

Step-by-step explanation:

Given functions are:

s(x)= x+6\\t(x)= 4x^2

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2

Also we have to find

(s-t)(x) => we have to subtract function t from function s

(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

(s+t)(x) = s(x)+t(x)\\= x+6+4x^2

Putting x = -3

= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39

Hence,

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

8 0
2 years ago
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