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Charra [1.4K]
3 years ago
9

You have 60 waffles in all with a serving size of 2 waffles, there are 4 people, how many days will the waffles last. Show equat

ion
Mathematics
1 answer:
Alja [10]3 years ago
5 0
30÷2 =60
15 days 4×7=
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Teresa, Eric, and Ryan sent a total of 99 text messages over their cell phones during the weekend. Eric sent 3 times as
faust18 [17]

I'll use t for the messages Teresa sent, e for messages Eric sent, and r for messages Ryan sent.

Therefore we have, t+e+r=99.

From the text we also know:

e=3r ; r=t+6

If we substitute in the original equation we get:

t+3(t+6)+t+6=99; By simplifying it we get

5t=75 , therefore t=75/5=15.

Since Teresa send 15 messages,Ryan sent 6 more then here, so he send 21. Eric sent three times the

messages Ryan sent so he sent 63 messages. If we add them together 15+21+63, we get the total of 99 messages.

8 0
3 years ago
Identify the independent variable and dependent variable in the situation:
kramer
I think the independent variable is the number of people and the dependent is the wait time. I see it as the wait time DEPENDS on how many people are in line. This one is kinda confusing tho
3 0
3 years ago
R = x(A + B)<br> Solve for A.
larisa86 [58]

Answer:

A = \frac{R}{x} - B

Step-by-step explanation:

Given

R = x(A + B) ← divide both sides by x

\frac{R}{x} = A + B ( subtract B from both sides )

\frac{R}{x} - B = A

3 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
What is the absolute value of -5/8?
Gemiola [76]

well, -5/8 is -0.625.

the absolute value of -0.625 is 0.625.

and abs value of -5/8 is 5/8

7 0
3 years ago
Read 2 more answers
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