Answer and Step-by-step explanation:
If the radius is 5, then we can plug 5 into the area of a circle equation.
A = 
A = 
A = 25
<u>The area of a circle with radius 5 is 25</u>
<u>.</u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Holy god gud luck on escaping that (*´ー`*)
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Answer:
1.187991
Step-by-step explanation:
sin^2(225)−(cos(330))(cos(240))
=(−0.930095)2−(cos(330))(cos(240))
=0.865076−(cos(330))(cos(240))
=0.865076−−0.991199(cos(240))
=0.865076−(−0.991199)(0.325781)
=0.865076−(−0.322914)
=1.187991