Find the point-slope form of the equation of the line passing through the points (–1, –3) and (4, 1).

Mathematics

2 answers:

Naily [24]3 years ago

6 0

Remember that point slope form is y-y1=m(x-x1)
Your y1 value is -3 and your x1 value is -1.
Before we can solve the equation, we need the slope first. To find the slope of a line, we need to use the equation y2-y1/x2-x1.
That would be 1-(-3)/4-(-1) which translates to 4/5. Your slope is 4/5.
Now we can plug this into the point slope form.
y-(-3)=4/5(x-(1))
That would be y+3=4/5x+4/5. You must then subtract 3 from 4/5.
This would mean that y=4/5x-2.2
Hope this helps.

IrinaK [193]3 years ago

5 0

The answer is given above

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Arturiano [62]

ANSWER
$x=4, y=8$

EXPLANATION

If ABCD is a parallelogram, then

line AB is parallel to line DC .

This means that,

$(x + 2) \degree$
and

$(2x - 2) \degree$
are alternating angles.

Alternate angles are congruent.

This implies that,

$2x - 2 = x + 2$

We group like terms to obtain,

$2x - x = 2 + 2$

This simplifies to,

$x = 4$

Also, if ABCD is a parallelogram then,

BC is parallel to AD. This means that,

$5y - 8 = y + 24$

We group like terms to get,

$5y - y = 24 + 8$

This simplifies to,

$4y = 32$

We divide both side by 4 to get,

$y = 8$