Find the point-slope form of the equation of the line passing through the points (–1, –3) and (4, 1).

Mathematics

2 answers:

Naily [24]3 years ago

6 0

Remember that point slope form is y-y1=m(x-x1)
Your y1 value is -3 and your x1 value is -1.
Before we can solve the equation, we need the slope first. To find the slope of a line, we need to use the equation y2-y1/x2-x1.
That would be 1-(-3)/4-(-1) which translates to 4/5. Your slope is 4/5.
Now we can plug this into the point slope form.
y-(-3)=4/5(x-(1))
That would be y+3=4/5x+4/5. You must then subtract 3 from 4/5.
This would mean that y=4/5x-2.2
Hope this helps.

IrinaK [193]3 years ago

5 0

The answer is given above

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The graph shown below expresses a radical function that can be written in the form f(x)= a(x + k)^1/n +C. What does the graph te

MAXImum [283]

Answer:

C. <em>c</em> is less than zero

Step-by-step explanation:

The parent radical function y=x^(1/n) has its point of inflection at the origin. The graph shows that point of inflection has been translated left and down.

<h3>Function transformation</h3>

The transformation of the parent function y=x^(1/n) into the function ...

f(x) = a(x +k)^(1/n) +c

represents the following transformations:

vertical scaling by a factor of 'a'
left shift by k units
up shift by c units

<h3>Application</h3>

The location of the inflection point at (-3, -4) indicates it has been shifted left 3 units, and down 4 units. In the transformed function equation, this means ...

k = 3
c = -4

The graph says the value of c is less than zero.

<em>Additional comment</em>

Apparently, the value of 'a' is 2, and the value of n is 3. The equation of the graph seems to be ...

f(x) = 2(x +3)^(1/3) -4

8 0

1 year ago

How do you do this problem 1/4 +4x/5=11/20?

Nutka1998 [239]

$\frac{1}{4}+\frac{4}{5}x=\frac{11}{20}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{1}{4}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{5}{20}\\\\\frac{4}{5}x=\frac{6}{20}\ \ \ \ \ \ \ |\cdot\frac{5}{4}\\\\x=\frac{30}{80}=\frac{3}{8}$