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kati45 [8]
3 years ago
13

How do you know a radical expression is in simplest form?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0
Answer: To know whether a radical expression is in simplest form or not you should put the numbers and letters inside the radical in terms of prime factors. Then, the radical expression is in the simplest form if all the numbers and letters inside the radical are prime factors with a power less than the index of the radical

Explanation:

Any prime factor raised to a power greater than the index of the root can be simplified and any factor raised to a power less than the index of the root cannot be simplified

For example simplify the following radical in its simplest form:


\sqrt[5]{3645 a^8b^7c^3}

1) Factor 3645 in its prime factors: 3645 = 3^6 * 5

2) Since the powr of 3 is 6, and  6 can be divided by the index of the root, 5, you can simplify in this way:

- 6 ÷ 5 = 1 with reminder 1, so 3^1 leaves the radical and 3^1 stays in the radical

3) since the factor 5 has power 1 it can not leave the radical

4) the power of a is 8, then:

8 ÷ 5 = 1 with reminder 3 => a^1 leaves the radical and a^3 stays inside the radical.

5) the power of b is 7, then:

7 ÷ 5 = 1 with reminder 2 => b^1 leaves the radical and b^2 stays inside the radical

6) the power of c is 3. Since 3 is less than 5 (the index of the radical) c^3 stays inside the radical.

7) the expression simplified to its simplest form is

3ab \sqrt[5]{3.5.a^3b^2c^3}

And you know it cannot be further simplified because all the numbers and letters inside the radical are prime factors with a power less than the index of the radical.
kow [346]3 years ago
6 0
To simplify, the trick is to split the number into factors where one is a perfect square. Expressing in simplest radical form<span> just means simplifying a </span>radical<span> so that there are no more square roots, cube roots, 4th roots, etc left to find. It also means removing any </span>radicals<span> in the denominator of a fraction.</span>
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Estimate the product by rounding 3x5,186
masya89 [10]
The estimation of the product would be around 15,600 because if you round 5,186, it will become 5,200. multiply that by 3, and that's where you get your answer
3 0
3 years ago
Find the distance between the two numbers on a number line. Write your answer as a fraction in simplest form. - 7/9, - 2/9 The d
Nesterboy [21]

The distance between the two points on the number line is of \mathbf{\frac{5}{9}} units.

-------------------------------------------

  • The distance between two numbers on the number line is given by the <u>subtraction of the greater by the smaller number.</u>
  • The greater number is -\frac{2}{9}
  • The smaller is -\frac{7}{9}.
  • The distance is:

-\frac{2}{9} - (-\frac{7}{9}) = -\frac{2}{9} + \frac{7}{9} = \frac{-2 + 7}{9} = \frac{5}{9}

Thus, distance of \mathbf{\frac{5}{9}} units.

A similar problem is given at brainly.com/question/10795861

8 0
3 years ago
Y=-0.72x + 7.7<br> Find y when x = 3.5.
OLEGan [10]

Answer:

y = 5.18

Step-by-step explanation:

replace x in the equation with 3.5

y = -0.72x + 7.7

y = -0.72(3.5) + 7.7

y = -2.52 + 7.7

y = 5.18

7 0
3 years ago
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What is the negative GCF for-3x -18?
Debora [2.8K]

Answer:

-3

Step-by-step explanation:

GCF = greatest common factor

What is in common with 3x and 18? They are both multiples of 3.

3 times x = 3x

3 times 6 = 18

However, it is -3x and -18

So we can add a negative sign in front of the 3

Therefore, the GCF is -3.

I hope this helped and please mark me as brainliest!

6 0
3 years ago
Mr. Lopez wrote the equation 32g+8g-10g=150 on the board. Four students explained how to solve for g. Alyssa: “I added 32 and 8
Vaselesa [24]

Answer:

Wilhem

Step-by-step explanation:

The given equation is

32g+8g-10g=150

Step 1 : Add 32g and 8g.

(32g+8g)-10g=150

(32+8)g-10g=150

40g-10g=150

Step 2: Subtract 10 from 40.

(40-10)g=150

30g=150

Step 3: Divide both sides by 30, find the value of g.

\frac{30g}{30}=\frac{150}{30}

g=5

The value of g is 5.

Therefore, Wilhem is correct.

7 0
3 years ago
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