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2 years ago

What is 19 divided by 4,257

Mathematics

2 answers:

antoniya [11.8K]2 years ago

8 0

The answer will be 9÷4257 = 0.004463

Mariulka [41]2 years ago

8 0

It should be 0.224 i think it should be

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2 years ago

Enter the correct answer in the box.<br> IF x≠0, what is the sum of 4 v^3 x^10 + 5x^3 ^3

dsp73

Answer: $14*\sqrt[3]{x^{10}}$

Step-by-step explanation:

First, let's remember the rules:

$x^{1/n} = \sqrt[n]{x}$

such that:

$\sqrt[n]{x^m} = x^{m/n}$

$(x^a)^b = x^{a*b}$

$x^a*x^b = x^{a + b}$

Now we have the equation:

$4*\sqrt[3]{x^{10}} + 5*x^3*\sqrt[3]{8*x}$

First, let's rewrite the roots as we saw above:

$4*x^{10/3} + 5*x^3*\sqrt[3]{8}*x^{1/3} = 4*x^{10/3} + 5*\sqrt[3]{8}*x^{3 + 1/3}$

We also know that: $\sqrt[3]{8} = 2$

and that: $3 + 1/3 = 9/3 + 1/3 = 10/3$

Replacing those two things in our equation, we get:

$4*x^{10/3} + 5*\sqrt[3]{8}*x^{3 + 1/3} = 4*x^{10/3} + 5*2*x^{10/3} = (4 + 5*2)*x^{10/3}$

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Where in the final step, I returned to the cubic root form.

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3 years ago

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

Komok [63]

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

$p + P(A) = 1$

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

First not lost(0.6 probability) and second lost(0.4 probability)

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

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2 years ago