Given:
The equation is

To find:
The formula where x is the subject of the given formula.
Solution:
To make x the subject of the formula, we need to isolate the variable x.
We have,

Subtracting p from both sides, we get



Therefore, the required formula of x is
.
The constant money u get every 1 hour
-1/2(-5/6+-1/3)
-1/2(-1/2)
1/4
<span>The variance method is as follows.
-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)
Our variance is
<span>

Since variance has to be 14, we set

and solve for m

quadratic formula

-4 doesnt' work as it is not a positive integer
m = 11
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