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Rufina [12.5K]
3 years ago
10

Mary wants to find the area of the rectangle below.

Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0
So first find the area
area=legnth times width
area=5/6 times 1/6
5/6 times 1/6=5/36
area=5/36 square units

tile=side legnth 1/6
area of tile=legnth times width or legnth times legnth
1/6 times 1/6=1/36
we must find how many times 1/36 goes into 5/36
divide 5/36 by 1/36
5/36 divided by 1/36=5/36 times 36/1=5/1 times 36/36=5/1 times 1=5

the answer is 5 unit squares needed to tile
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What is the slope of the line passing thru the points (-6,-5) (4,4)
Katena32 [7]

Answer:

slope = \frac{9}{10}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (4, 4)

m= \frac{4+5}{4+6} = \frac{9}{10}

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3 years ago
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Step-by-step explanation:

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3 years ago
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3 years ago
Write an equation for the translation of x^2 + y^2 = 49 by 7 units right and 4 units up
Tatiana [17]

Answer:

(x - 7)² + (y - 4)² = 49

Step-by-step explanation:

Given

Equation: x² + y² = 49

Required:

New Equation when translated 7 units right and 4 units up

Taking it one step at a time.

When the equation is translated 7 units right, this implies a negative unit along the x axis.

The equation becomes

(x - 7)² + y² = 49

When the equation is translated 4 units up, this implies a negative unit along the y axis.

(x - 7)² + (y - 4)² = 49

The expression can be further simplified but it's best left in the form of

(x - 7)² + (y - 4)² = 49

8 0
3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
f(x) = a(x - x_1)(x-x_2)(x-x_3)

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form (x_n , 0)

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
f(x) = a (x-2)(x-3)(x-5)
              = a[(x^2 - 2x - 3x + 6)(x-5)]
              = a[(x^2 - 5x+6)(x-5)]
              = a(x^3 - 5x^2 + 6x- 5x^2 + 25x - 30)
              = a(x^3 - 10x^2+31x-30)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
-5= a (0-0+0 - 30)
-5 = -30a
a =  \frac{-5}{-30} =  \frac{1}{6}
So required equation of cubic polynomial is
f(x) =  \frac{1}{6}(x^3 -10x^2+31x-30)

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
4 0
3 years ago
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