Answer:
Step-by-step explanation:
The first parabola has vertex (-1, 0) and y-intercept (0, 1).
We plug these values into the given vertex form equation of a parabola:
y - k = a(x - h)^2 becomes
y - 0 = a(x + 1)^2
Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:
1 = a(0 + 1)^2, and from this we know that a = 1. Thus, the equation of the first parabola is
y = (x + 1)^2
Second parabola: We follow essentially the same approach. Identify the vertex and the two horizontal intercepts. They are:
vertex: (1, 4)
x-intercepts: (-1, 0) and (3, 0)
Subbing these values into y - k = a(x - h)^2, we obtain:
0 - 4 = a(3 - 1)^2, or
-4 = a(2)². This yields a = -1.
Then the desired equation of the parabola is
y - 4 = -(x - 1)^2
Answer: with question 1 mark your first line by having it intercept at postive 4 on y axis then count up 1 right 4 then mark a point then mark a point down 1 left 4 then create your line
After that line go to next line but starting at -3 on y axis then go up three left 2 until you cant fit on graph you should get your answer where both lines you draw cross at
Step-by-step explanation:
In the equation y=mx+b, the variable m represents the slope of the line. Therefore, the equation -5x+2y=10 can be rearranged into 2y=5x+10. Isolate the y to get y=2.5x+5. The slope of the line is 2.5
The answer is
x = 1 and y = -3
<span>[1] 6x-9=y
[2] y=-3x</span>
