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AlladinOne [14]
4 years ago
8

Given ΔMNO, find the measure of ∠MNO. Triangle MNO with segment LM forming a straight angle with segment MO and segment OP formi

ng a straight angle with segment MO, the measure of angle NOP is 104 degrees, and segment MN and NO are marked congruent. 28° 38° 52° 76°

Mathematics
2 answers:
NeTakaya4 years ago
7 0

Answer:

HIS ANSWER IS WRONG ITS 28

Step-by-step explanation:

MrMuchimi4 years ago
5 0

Answer:

Alrighty The correct answer my friend IS 52

Step-by-step explanation:

if it isnt the right anser dont do 38 or 76 because i took the test and got both of those wrong.

Sincerely barrydadarry

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Store A sells boxes of rice for $2.50 each.
lawyer [7]
The answer I think is 5 because
6 0
3 years ago
Quadratic formula. pls help
crimeas [40]

Answer:

x=-1,\frac{5}{7}

Step-by-step explanation:

1) Split the second term in 7{x}^{2}+2x-5 into two terms.

1 - Multiply the coefficient of the first term by the constant term.

7\times -5=-35

2 - Ask: Which two numbers add up to 2 and multiply to -35?

7 and -5.

3 - Split 2x as the sum of 7x and -5x.

7x^2+7x-5x-5

2)  Factor out common terms in the first two terms, then in the last two terms.

7x(x+1)-5(x+1)=0

3) Factor out the common term x+1.

(x+1)(7x-5)=0

4) Solve for x.

1 - Ask: When will (x+1)(7x-5) equal zero?

When x + 1 0 or 7x-5=0

2 - Solve each of the 2 equations above.

x=-1,\frac{5}{7}

8 0
2 years ago
Read 2 more answers
In the adjoining figure, ABC is a right-angled triangle, where
zimovet [89]

Answer:

the value of theta i 45°

3 0
4 years ago
Mr. Ayer cuts one melon into 8 equal pieces. write the number 1 as a sum unit fractions that name each piece of melon.
sertanlavr [38]
It would split up in eighths. So it would be like 1/8, 2/8, 3/8 ....
6 0
4 years ago
Hich function has a range of {y|y ≤ 5}?
marshall27 [118]

Answer:

f(x)=-(x-4)^{2}+5

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

<u>Verify each case</u>

case A) f(x)=(x-4)^{2}+5

The vertex is the point (4,5)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

y\geq5

case B) f(x)=-(x-4)^{2}+5

The vertex is the point (4,5)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

y\leq 5

case C) f(x)=(x-5)^{2}+4

The vertex is the point (5,4)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

y\geq4

case D) f(x)=-(x-5)^{2}+4

The vertex is the point (5,4)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

y\leq 4

4 0
3 years ago
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