All categories

2 years ago

What is 29 divided by 11

Mathematics

2 answers:

dezoksy [38]2 years ago

4 0

Answer:

2.63

Step-by-step explanation:

29/11=2.63

mariarad [96]2 years ago

3 0

Answer:

2.64

Step-by-step explanation:

First you Set the problem up like

11/29

then you take

11/29

11x2= 22

You might be interested in

Need help please just have to solve

saul85 [17]

CAN BARELY SEE ANYTHING

7 0

2 years ago

The data plan for Shawn's phone has 32,000 megabytes of storage for photos. She wants to increase the amount of data by 4%. If e

mixer [17]

You need to do 32,000/100 which is 320 and then multiply this by 4. This is 1280. Now you need to divide 1280 by 5 which is 256.

This means that she can get 256 new photos, so yes, she can get 200 more photos.

Hope this helps x

4 0

2 years ago

Read 2 more answers

Do teachers find their work rewarding and satisfying? An article reports the results of a survey of 397 elementary school teache

Tju [1.3M]

Answer:

The 95% confidence interval would be given (0.0109;0.1651).

We are confident at 95% that the difference between the two proportions is between $0.0109 \leq p_{elementary} -p_{High school} \leq 0.1651$

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for elementary school

$\hat p_A =\frac{226}{397}=0.569$ represent the estimated proportion for elementary school

$n_A=397$ is the sample size required for Brand A

$p_B$ represent the real population proportion for high school teachers

$\hat p_B =\frac{129}{268}=0.481$ represent the estimated proportion for high school teachers

$n_B=268$ is the sample size required for Brand B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.