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3 years ago

Can somebody help me with this problem!? i need help ahh

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer:

134 Degrees.

Step-by-step explanation:

Lets figure out the third angle (y) in the triangle first.

70 + 64 + y = 180

134 + y = 180

y = 46

We now know that 46 is our third angle. Therefore, we can subtract 46 (y) from 180 (the total between x and the third angle) to get our final answer. 134 Degrees.

slamgirl [31]3 years ago

6 0

for these kinds of problems the outside angle always equals the opposite 2. meaning angle x=64+70 which is 134 degrees. you can double check this because all triangles equal 180 degrees. meaning that the last angle in the triangle is 46. 46+70+64=180.

so your answer is 134.

hope this helps :)

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7/5 + 3/8 =what /40 + what/40 = ?/?

VARVARA [1.3K]

Answer:

71/40

Step-by-step explanation:

7/5*8/8=56/40+3/8*5/5= 15/40 so 15/40+56/40=71/40

6 0

4 years ago

Jill arranged her baseball cards in 4 rows of 9 cards then she arranged the cards in 2 rows of 18 cars how many other ways can J

Ronch [10]

She can arrange them in the following;
1 row of 36
2 rows of 18 (doesnt count because it says other and this has already been mentioned)
3 rows of 12
4 rows of 9 (doesnt count because it says other and this has already been mentioned)
6 rows of 6

3 0

3 years ago

Read 2 more answers

A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud

8_murik_8 [283]

Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

$\bar x = 7.10$ -- sample mean

$\sigma=5$ --- sample standard deviation

$n = 150$ --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

$CI = 90\%$ --- the confidence interval

Calculate the $\alpha$ level

$\alpha = 1 - CI$

$\alpha = 1 - 90\%$

$\alpha = 1 - 0.90$

$\alpha = 0.10$

Divide by 2

$\frac{\alpha}{2} = 0.10/2$

$\frac{\alpha}{2} = 0.05$

Subtract from 1

$1 - \frac{\alpha}{2} = 1 - 0.05$

$1 - \frac{\alpha}{2} = 0.95$

From the z table. the critical value for $1 - \frac{\alpha}{2} = 0.95$ is:

$z = 1.960$

Solving (c): Margin of error

This is calculated as:

$E = z * \frac{\sigma}{\sqrt n}$

$E = 1.960 * \frac{5}{\sqrt {150}}$

$E = 1.960 * \frac{5}{12.25}$

$E = \frac{1.960 *5}{12.25}$

$E = \frac{9.80}{12.25}$

$E = 0.800$

Solving (d): The confidence interval

This is calculated as:

$CI = (\bar x - E, \bar x + E)$

$CI = (7.10 - 0.800, 7.10 + 0.800)$

$CI = (6.3, 7.9)$

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0

3 years ago

A bank exchanges United States currency for British courrency at the rate of 1.60 dollars to the £ .

kompoz [17]

Answer:

Remember that £ has a greater value compared to $ and vice versa.

5 0

3 years ago

A centipede is crawling 6 inches per minute. how long will it take the centipede to travel 1 yard?

Ede4ka [16]

6 minutes, because 1 yd is equivalent to 3 feet, which is equivalent to 36 inches. If a centipede crawls at 6 inches per minute, you do 6 x 6, which equals 36, and get 6 minutes!

3 0

3 years ago