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PIT_PIT [208]
3 years ago
11

Can somebody help me with this problem!? i need help ahh

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

134 Degrees.

Step-by-step explanation:

Lets figure out the third angle (y) in the triangle first.

70 + 64 + y = 180

134  + y = 180

y = 46

We now know that 46 is our third angle. Therefore, we can subtract 46 (y) from 180 (the total between x and the third angle) to get our final answer. 134 Degrees.

slamgirl [31]3 years ago
6 0

for these kinds of problems the outside angle always equals the opposite 2. meaning angle x=64+70 which is 134 degrees. you can double check this because all triangles equal 180 degrees. meaning that the last angle in the triangle is 46. 46+70+64=180.

so your answer is 134.

hope this helps :)

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7/5 + 3/8 =what /40 + what/40 = ?/?
VARVARA [1.3K]

Answer:

71/40

Step-by-step explanation:

7/5*8/8=56/40+3/8*5/5= 15/40 so 15/40+56/40=71/40

6 0
4 years ago
Jill arranged her baseball cards in 4 rows of 9 cards then she arranged the cards in 2 rows of 18 cars how many other ways can J
Ronch [10]
She can arrange them in the following;
1 row of 36
2 rows of 18 (doesnt count because it says other and this has already been mentioned)
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3 0
3 years ago
Read 2 more answers
A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud
8_murik_8 [283]

Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

\bar x = 7.10 -- sample mean

\sigma=5 --- sample standard deviation

n = 150 --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

CI = 90\% --- the confidence interval

Calculate the \alpha level

\alpha = 1 - CI

\alpha = 1 - 90\%

\alpha = 1 - 0.90

\alpha = 0.10

Divide by 2

\frac{\alpha}{2} = 0.10/2

\frac{\alpha}{2} = 0.05

Subtract from 1

1 - \frac{\alpha}{2} = 1 - 0.05

1 - \frac{\alpha}{2} = 0.95

From the z table. the critical value for 1 - \frac{\alpha}{2} = 0.95 is:

z = 1.960

Solving (c): Margin of error

This is calculated as:

E = z * \frac{\sigma}{\sqrt n}

E = 1.960 * \frac{5}{\sqrt {150}}

E = 1.960 * \frac{5}{12.25}

E =  \frac{1.960 *5}{12.25}

E =  \frac{9.80}{12.25}

E =  0.800

Solving (d): The confidence interval

This is calculated as:

CI = (\bar x - E, \bar x + E)

CI = (7.10 - 0.800, 7.10 + 0.800)

CI = (6.3, 7.9)

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0
3 years ago
A bank exchanges United States currency for British courrency at the rate of 1.60 dollars to the £ .
kompoz [17]

Answer:

Remember that £ has a greater value compared to $ and vice versa.

5 0
3 years ago
A centipede is crawling 6 inches per minute. how long will it take the centipede to travel 1 yard?
Ede4ka [16]
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3 0
3 years ago
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