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PIT_PIT [208]
3 years ago
11

Can somebody help me with this problem!? i need help ahh

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

134 Degrees.

Step-by-step explanation:

Lets figure out the third angle (y) in the triangle first.

70 + 64 + y = 180

134  + y = 180

y = 46

We now know that 46 is our third angle. Therefore, we can subtract 46 (y) from 180 (the total between x and the third angle) to get our final answer. 134 Degrees.

slamgirl [31]3 years ago
6 0

for these kinds of problems the outside angle always equals the opposite 2. meaning angle x=64+70 which is 134 degrees. you can double check this because all triangles equal 180 degrees. meaning that the last angle in the triangle is 46. 46+70+64=180.

so your answer is 134.

hope this helps :)

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The larger of two numbers is 7 more than 5 times the other. Their sum is 55. Find the two numbers.
viva [34]

Answer:

Step-by-step explanation:

8 and 47

7 0
3 years ago
Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies ac
Shtirlitz [24]

Answer:

a) \mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

b) For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

Step-by-step explanation:

Assuming this question : "Bigger animals tend to carry their young longer before birth. The  length of horse pregnancies from conception to birth varies according to a roughly normal distribution with  mean 336 days and standard deviation 6 days. Use the 68-95-99.7 rule to answer the following questions. "

(a) Almost all (99.7%) horse pregnancies fall in what range of lengths?

First we need to remember the concept of empirical rule.

From this case we assume that X\sim N(\mu = 336. \sigma =6) where X represent the random variable "length of horse pregnancies from conception to birth"

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

From the empirical rule we know that we have 99.7% of the data within 3 deviations from the mean so then we can find the limits for this case with this:

\mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

(b) What percent of horse pregnancies are longer than  342 days?

For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

7 0
3 years ago
Pls help will give brainliest and 5star and thanks plss help
Katarina [22]

Answer:

1. 17 centimeters

2. 25 feet

3. 12 yards


5 0
3 years ago
Write 3 1/8% as fraction in simplest form
PolarNik [594]

so change a value to a percentage format, we simply divide it by 100.

for example, 2% can be rewritten as 2/100 or 0.02 in decimal format.


now, let's first convert the mixed fraction to improper, and then do the percentage format and simplification.


\bf \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{~~\frac{25}{8}~~}{100}\implies \cfrac{~~\frac{25}{8}~~}{\frac{100}{1}}\implies \cfrac{25}{8}\cdot \cfrac{1}{100}\implies \cfrac{1}{8}\cdot \cfrac{25}{100}\implies \cfrac{1}{8}\cdot \cfrac{1}{4}\implies \cfrac{1}{32}

8 0
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Luba_88 [7]

9514 1404 393

Answer:

  (a) The set must have a constant additive rate of change

Step-by-step explanation:

If a linear function is suitable for representing the data, the data will demonstrate a constant slope. That is, for evenly spaced values of the independent variable, the differences of the values of the dependent variable will be constant. We can say ...

  The set must have a constant additive rate of change.

8 0
3 years ago
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