Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
a number hahah
Step-by-step explanation:
as i guess i think haha
Answer:
56.25 ft
Step-by-step explanation:
It is simple, since it is a square the sides are all the same length so you take A=area and divide it by four= h or w or l (height, width, length) so
225/4=56.25
Answer:
8 cookies
Step-by-step explanation:
edit one:the answer was 10 cookies, so please go give the person who said 10 cookies first some thanks/brainliest.
edit two:brainly.com/app/profile/31525083 is the user who got it first. Check comment if you are gonna say they didn't.
Answer:
Hello! After reading your question I have deduced that the correct answer is 288² cm.
Step-by-step explanation:
The way I came to this conclusion was as follows:
Firstly:
If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.
This is because all four sides of a square have to be equal.
Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.
Thus both of the squares are going to be the same size, so they will have the same area.
Secondly:
If the area of one square is 144² cm then the area of the other square should also be 144² cm.
Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.
I hope this helped!
