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Stells [14]
4 years ago
15

Evaluate the expession. x=12, y=8, z=3 4x-yz

Mathematics
2 answers:
Nataly_w [17]4 years ago
8 0
Given:
<span> x=12,  y=8, z=3

4x-yz = 4(12) - (8)(3)
</span>4x-yz = 48 - 24
4x-yz = 24
suter [353]4 years ago
7 0
Answer is 24 ..............;)
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During a rodeo, a clown runs 8.0 m north, turns 55° north of east, and runs 3.5 m. then, after waiting for the bull to come near
tino4ka555 [31]
We calculate for the x- and y-components of the distances traveled by the clown.

First: 8.0 m north

x-component = 0 m
y-component = +8 m

Second: 55° north of east (3.5 m)

x-component = (3.5 m)(cos 55°) = 2 m
y-component = (3.5 m)(sin 55°) = 2.87 m

Third: 5 m east

x-component = 5 m
y-component = 0 m

The total x-component is equal to 7 m and the y-component is equal to 10.87 m. 

The displacement is,

   c = sqrt((7 m)² + (10.87 m)²) 
  
   c = 12.93 m

<em>Answer: 12.93 m</em>
7 0
3 years ago
$16.99 multiplied by 0.94 euro
Butoxors [25]
The answer is 15.9706
4 0
3 years ago
Can the polynomial below be factored into a perfect square? If not, select the answer that best describes why not.
zaharov [31]
Option B;
A suitable x-coefficient for a quadratic function that factors into a perfect square has to be even.
8 0
4 years ago
Read 2 more answers
X 49°<br> 14 <br> i will give points!!
Pachacha [2.7K]

In the given diagram, the length of the side marked x is 21.34

<h3>Trigonometry </h3>

From the question, we are to determine the value of the side marked x

In the given diagram,

Hypotenuse = x

Adjacent = 15

Included angle = 49°

Using SOH CAH TOA

We can write that,

cos 49° = 14 / x

∴ x = 14 / cos 49°

x = 21.34

Hence, the length of the side marked x is 21.34.

Learn more on Trigonometry here: brainly.com/question/23505834

#SPJ1

7 0
2 years ago
Identify the function that contains the data in the following table: x     -2         0         2         3         5     f(x)  
Veseljchak [2.6K]

Answer:

f(x) = |x - 2| + 1

Step-by-step explanation:

When x = -2, then f(-2) = 5

The first function gives the relation equation as f(x) = |x| + 1

So, f(-2) = |-2| + 1 = 2 + 1 = 3 ≠ 5

{Since the definition of |x| is given by  

|x| = x, when x ≥ 0 and |x| = - x, when x < 0}

Again, the second  function gives the relation equation as f(x) = |x - 2|.

So, f(-2) = |-2 - 2| = |-4| = 4 ≠ 5

Now, the third function gives the relation equation as f(x) = |x - 2| - 1.

So, f(-2) = |-2 - 2| - 1 = |-4| - 1 = 4 - 1 = 3 ≠5

Again, the fourth function gives the relation equation as f(x) = |x - 2| + 1.

Hence, f(-2) = |-2 - 2| + 1 = |-4| + 1 = 4 + 1 = 5  

Therefore, the fourth function f(x) = |x - 2| + 1 contains the given data table.  

For further clarity we can check f(0) = 3, f(2) = 1, f(3) = 2 and f(5) = 4. (Answer)

6 0
4 years ago
Read 2 more answers
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