Answer:
Step-by-step explanation:
Confidence interval for the difference in the two proportions is written as
Difference in sample proportions ± margin of error
Sample proportion, p= x/n
Where x = number of success
n = number of samples
For the men,
x = 318
n1 = 520
p1 = 318/520 = 0.61
For the women
x = 379
n2 = 460
p2 = 379/460 = 0.82
Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]
To determine the z score, we subtract the confidence level from 100% to get α
α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
This is the area in each tail. Since we want the area in the middle, it becomes
1 - 0.025 = 0.975
The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96
Margin of error = 1.96 × √[0.61(1 - 0.61)/520 + 0.82(1 - 0.82)/460]
= 1.96 × √0.0004575 + 0.00032086957)
= 0.055
Confidence interval = 0.61 - 0.82 ± 0.055
= - 0.21 ± 0.055
Add the two monthly incomes together:
1400 + 1100 = 2500 a month.
There are 12 months in a year, multiply the monthly income by 12:
2500 * 12 = $30,000 per year.
Answer:10 Tablets must be taken
Step-by-step explanation:
V=5
5×2=10
Answer:
Differential equation
Solution
Value of constant k=0.327 days^(-1)
The rumor reaches 80% at 8.48 days.
Step-by-step explanation:
We know
y(t): proportion of people that heard the rumor
y'(t)=ky(1-y), rate of spread of the rumor
Differential equation
Solving the differential equation
Initial conditions:
Value of constant k=0.327 days^(-1)
At what time the rumor reaches 80%?
The rumor reaches 80% at 8.48 days.
For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
