Answer:
Number of bacteria when t = 10 min is 3,000
Step-by-step explanation:
Given:
Number of bacteria in a culture by equation
Q(t) = 2(729^t)
Value of t = 10 min = 10 / 60 = 0.1667 hour
where t is number of hours
Find:
Number of bacteria when t = 0.1667 hour
Computation:
Given equation
Q(t) = 2(729^t)
Put t = 0.1667
Q(10) = 2(729⁰'¹⁶⁶⁷)
We know that;
a⁰ = 1
So,
Q(0.1667) = 2(729⁰)
Q(0.1667) = 3
Number of bacteria when t = 0 is 3,000
Answer:
Step-by-step explanation:
Radicals and imaginary numbers ALWAYS come in pairs when it comes to factors of polynomials. This is the called the conjugate theorem. If we are given a solution/root/zero that is
x = 3 + √5, then its conjugate is x = 3 - √5. Going backwards from the solution to the factor, we utilize the Zero Product Property and get
(x - (3 - √5)) which simplifies to (x - 3 + √5). if you are looking for the conjugate of the given zero, the choice you want is the second one down.
3r + 2rt = 18
r is the common factor
r(3 + 2t) = 18
r= 18/ 3 + 2t
r= 6 + 9t
Hope this helps!
The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.
<h3>Why should the second arc be centered at C?</h3>
The second arc should be centered at C because as it crosses passing through Line C, it is seen that it was not touching or intersecting AB and so one can say that it is parallel to it.
Looking at the other lines, we will see that they are all touching AB and are not running parallel to it.
Hence, The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.
Learn more about line parallel;
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Answer:
The number 2
Step-by-step explanation:
