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Kay [80]
3 years ago
10

Ebony walked at arate of 3 1/2 miles per hour for 1 1/3 how far did she walk?

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

let's firstly convert the mixed fractions to improper fractions.


\bf \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}}~\hfill \stackrel{mixed}{1\frac{1}{3}}\implies \cfrac{1\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{4}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2}\\ \frac{7}{2}&1\\[0.8em] m&\frac{4}{3} \end{array}\implies \cfrac{~~\frac{7}{2}~~}{m}=\cfrac{~~1~~}{\frac{4}{3}}\implies \cfrac{7}{2m}=\cfrac{3}{4}\implies 28=6m \\\\\\ \cfrac{28}{6}=m\implies \cfrac{14}{3}=m\implies 4\frac{2}{3}=m

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Step-by-step explanation:

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Bezzdna [24]

Answer:

The equation for rational function for given asymptotes is

f(x)=(-4x^2-6)/{(x-3)(x+3)}

Step-by-step explanation:

Given:

vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at

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To find:

equation of a rational function i.e function in form p/q

Solution;

the equation should be in form of p/q

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denominator becomes, (x-3) and (x+3)

for horizontal asymptote to exist there should have same degrees  in numerator and denominator which of '2'

when g(x) will be degree '2' with -4 as coefficient and dont have  any real.

zero.

By horizontal asymptote  will be (-4x^2 -6)

The rational function is given by

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