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Dmitrij [34]
3 years ago
11

What unit is used to measure the downwards force of weight?

Physics
1 answer:
notka56 [123]3 years ago
7 0

Answer: Newton denoted using N

Examples: 25 N

Please rate 5 stars and vote as brainliest:)

(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)

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The mysterious visitor that appears in the enchanting story The Little Prince was said to come from a planet that "was scarcely
FromTheMoon [43]

Answer:

Part a)

g = 1 \times 10^{-5} m/s^2

Part b)

v = 0.011 m/s

Explanation:

Part a)

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

g = \frac{G(\frac{4}{3}\pi R^3 \rho)}{R^2}

g = \frac{4}{3}\pi \rho G R

now we know that

\rho = \frac{M}{\frac{4}{3}\pi R^3}

\rho = \frac{5.98 \times 10^{24}}{\frac{4}{3}\pi (6.37 \times 10^6)^3}

\rho = 5523.2 kg/m^3

now we have

g = \frac{4}{3}\pi (5523.2) (6.67 \times 10^{-11})(6.5)

g = 1 \times 10^{-5} m/s^2

Part b)

As we know that the escape speed is given as

v = \sqrt{\frac{2GM}{R}}

v = \sqrt{2gR}

v = \sqrt{2(1\times 10^{-5})(6.5)}

v = 0.011 m/s

8 0
3 years ago
A 70-kg astronaut is space walking outside the space capsuleand is stationary when the tether line breaks. As a means of returni
Bogdan [553]

Answer:

0.4 m/s

Explanation:

Law of conservation of momentum tell us that the change in momentum of the hammer will be equal to the change in momentum of the astronaut

change in momentum of hammer = change in momentum of astronaut

2 kg (14 m/s - 0 m/s) = 70 kg * (v-0)

                                v  = 0.4 m/s

7 0
3 years ago
Read 2 more answers
A 25.0 kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motio
QveST [7]

Answer:

(a) 0.31

(b) 0.245

Explanation:

(a)

F' = μ'mg.................... Equation 1

Where F' = Horizontal Force required to set the block in motion, μ' = coefficient of static friction, m = mass of the block, g = acceleration due to gravity.

make μ' the subject of the equation above

μ' = F'/mg............. Equation 2

Given: F' = 75 N, m = 25 kg

constant: g = 9.8 m/s²

Substitute these values into equation 2

μ' = 75/(25×9.8)

μ' = 75/245

μ' = 0.31.

(b) Similarly,

F = μmg.................. Equation 3

Where F = Horizontal force that is required to keep the block moving with constant speed, μ = coefficient of kinetic friction.

make μ the subject of the equation

μ = F/mg.............. Equation 4

Given: F = 60 N, m = 25 kg, g = 9.8 m/s²

Substitute these values into equation 4

μ  = 60/(25×9.8)

μ = 60/245

μ = 0.245

3 0
3 years ago
You have been hired as a technical consultant for an early-morning cartoon series for children to make sure that the science is
katen-ka-za [31]

The initial potential energy of the wagon containing gold boxes will enable

it roll down the hill when cut loose.

The Lone Ranger and Tonto have approximately <u>5.1 seconds</u>.

Reasons:

Mass wagon and gold = 166 kg

Location of the wagon = 77 meters up the hill

Slope of the hill = 8°

Location of the rangers = 41 meters from the canyon

Mass of Lone Ranger, m₁ = 65 kg

Mass of Tonto m₂ = 66 kg

Solution;

Height of the wagon above the level ground, h = 77 m × sin(8°) ≈ 10.72 m

Potential energy = m·g·h

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Potential energy of wagon, P.E. ≈ 166 × 9.81 × 10.72 = 17457.0912

Potential energy of wagon, P.E. ≈ 17457.0912 J

By energy conservation, P.E. = K.E.

K.E. = \mathbf{\dfrac{1}{2} \cdot m \cdot v^2}

Where;

v = The velocity of the wagon a the bottom of the cliff

Therefore;

\dfrac{1}{2} \times 166 \times v^2 = 17457.0912

v = \sqrt{\dfrac{17457.0912}{\dfrac{1}{2} \times 166} } \approx 14.5

Velocity of the wagon, v ≈ 14.5 m/s

Momentum = Mass, m × Velocity, v

Initial momentum of wagon = m·v

Final momentum of wagon and ranger = (m + m₁ + m₂)·v'

By conservation of momentum, we have;

m·v = (m + m₁ + m₂)·v'

\therefore v' = \mathbf{ \dfrac{m \cdot v}{(m + m_1 + m_2)  }}

Which gives;

\therefore v' = \dfrac{166 \times 14.5}{(166 + 65 + 66)  } \approx 8.1

The velocity of the wagon after the Ranger and Tonto drop in, v' ≈ 8.1 m/s

Time = \dfrac{Distance}{Velocity}

\mathrm{The \ time \ the\ Lone \  Ranger \  and  \ Tonto \  have,  \ t} = \dfrac{41 \, m}{8.1 \, m/s} \approx 5.1 \, s

The Lone Range and Tonto have approximately <u>5.1 seconds</u> to grab the

gold and jump out of the wagon before the wagon heads over the cliff.

Learn more here:

brainly.com/question/11888124

brainly.com/question/16492221

5 0
3 years ago
Which form of energy is due to the movement of electrons?​
larisa86 [58]

Kinetic energy is motion of waves, electrons, atoms, molecules, substances, and objects. Potential energy is stored energy and the energy of position gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges.

I hope this helps you.

8 0
3 years ago
Read 2 more answers
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