All categories

3 years ago

A father and his son want to play on a seesaw. Where on the seesaw should each of them sit to balance the torque?

Physics

1 answer:

vladimir1956 [14]3 years ago

3 0

Answer:

A The father should sit closer to the pivot.

C The longer wrench makes the job easier because less force is needed when there is more distance from the pivot.

A As far from the head of the hammer as possible because this will maximize torque.

D at the opposite side of the seesaw towards the middle

:) gl

Explanation:

You might be interested in

Heat is the transfer of thermal energy from one object to another because of a difference in

svetoff [14.1K]

I believe its temperature because when something has high temperature it has more thermal energy and when something has low temperature, it has less thermal energy. Hope that helped ^-^

8 0

3 years ago

A light-rail commuter train speeds up at a rate of 1.65 m/s 2 and takes 19.0 s to reach its top speed. How far down the tracks d

Margarita [4]

Answer:

297.8 m

Explanation:

We are given that

Acceleration= $a=1.65m/s^2$

Time,t=19 s

We have to find the distance covered by the train when it reach its top speed if starting from rest.

Initial speed=u=0

$s=ut+\frac{1}{2}at^2$

Using the formula

$s=0(19)+\frac{1}{2}\times 1.65(19)^2$

$s=297.8 m$

Hence, the train covered 297.8 m when the train go to reach its top speed if starting from rest.

7 0

3 years ago

Consider two point charges located on the x axis: one charge, q1 = -11.5nC , is located at x1 = -1.685m ;the second charge, q2 =

Nata [24]

Answer:

$F_{t3}=-3.76\ 10^{-5}\ N$

The net force is pointed to the left side

Explanation:

Electrostatic Force

The formula to compute the electrostatic force between two point charges was introduced by Charles Coulomb and it's expressed as

$\displaystyle F=\frac{k\ q_1\ q_2}{r^2}$

Where q1 and q2 are the magnitudes of the charges, r is the distance between them and k is a proportionality constant

The data provided in the problem is

$\displaystyle x_1=-1,685\ m$

$\displaystyle q_1=-11.5\ nC$

$\displaystyle q_2=40\ nC$

$\displaystyle q_3=55\ nC$

$\displaystyle x_3=-1.195\ m$

The distance between the charge 1 and 3 is

$\displaystyle d_{13}=1.685-1.195$

$\displaystyle d_{13}=0.49\ m$

The distance between charges 2 and 3 is

$\displaystyle d_{23}=1.195\ m$

Now, let's compute the force exerted by q1 on q3

$\displaystyle F_{13}=\frac{k\ q_1\ q_3}{d_{13}^2}$

$\displaystyle F_{13}=\frac{9\ 10^9\ 11.5\ 10^{-9}\ 55\ 10^{-9}}{0.49^2}$

$\displaystyle F_{13}=2.37\ 10^{-5}\ N$

This value is the scalar magnitude of the force, we'll take care of the directions later. The force by q2 on q3 is

$\displaystyle F_{23}=\frac{k\ q_2\ q_3}{d_{23}^2}$

$\displaystyle F_{23}=\frac{9\ 10^{9}\ 40\ 10^{-9}\ 55\ 10^{-9}}{1.195^2}$

$\displaystyle F_{23}=1.39\ 10^{-5}\ N$

Given that q1 is negative and q3 is positive, q1 attracts q3 to the left, so F13 is in the negative direction. The charge q2 is positive and repels q3 to the left, thus F23 is also negative. This leads us to compute the total force on q3 as

$\displaystyle F_{t3}=-F_{13}-F_{23}$

$\boxed{F_{t3}=-3.76\ 10^{-5}\ N}$

The net force is pointed to the left side

4 0

3 years ago

The Andromeda galaxy is moving toward us at 3.01x10^5 m/s. By how much will the frequency of the 6.17x10^14 Hz hydrogen line be

just olya [345]

Answer:

f - f '= 6.18*10^11 Hz

Explanation:

The change in frequency is given by:

$\frac{1}{f'}=\frac{1}{f}\frac{\sqrt{1+v/c}}{\sqrt{1-v/c}}$

f': observed frequency

f: source frequency = 6.17*10^14 Hz

v: speed of the source = 3.01*10^55 m/s

c: speed of light = 3*10^8 m/s

By replacing all these values you obtain:

$\frac{1}{f'}=\frac{1}{6.17x10^{14} Hz}\frac{\sqrt{1+(3.01*10^5m/s)(3*10^8m/s)}}{\sqrt{1-(3.01*10^5m/s)(3*10^8m/s)}}=1.62*10^{-15}\\\\f'=6.16*10^{14}Hz$

hence, the change in frequency f-f' will be:

f - f '= 6.18*10^11 Hz

4 0

3 years ago

The box is pulled horizontally across the floor by a force of 100 N and opposed by a frictional force of 60 N. The object accele

dalvyx [7]

Answer:

10 kg

Explanation:

first find resultant force by subtracting the forces
mass is force ÷ acceleration

7 0

3 years ago