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KiRa [710]
3 years ago
14

48 divided by four fifths

Mathematics
1 answer:
Fed [463]3 years ago
4 0

Answer:

The answer is 60.

Step-by-step explanation:

\frac{48}{1}÷\frac{4}{5}

Now, apply the fraction rule(\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}):

\frac{48}{1}×\frac{5}{4}

Cross-cancel(common factor of 4):

\frac{12}{1}×\frac{5}{1}

Multiply:

\frac{12 x 5}{1 x 1}

Simplify:

12 x 5=60

The answer is 60

hope this helps :)

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What is 1/6d+2/3 = 1/4(d-2)
GenaCL600 [577]
1/6d + 2/3 = 1/4(d - 2)

First, simplify \frac{1}{6} d to \frac{d}{6} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{1}{4} (d - 2)
Second, simplify \frac{1}{4} (d - 2) to \frac{d-2}{4} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{d-2}{4}
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
Sixth, simplify 3d - 6 - 2d to d - 6 / Your problem should look like: 8 = d - 6
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3 0
3 years ago
WILL GIVE BRAINLIEST IF CORRECT ANSWER!!!
Rom4ik [11]

Answer : 2√3

<u>Given </u><u>:</u><u>-</u>

  • A equilateral triangle with side length 4.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in the given figure.

As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .

  • So the perpendicular drawn in the figure will bisect the given side .
  • Therefore the value of each half will be 4/2 = 2 .

Now we may use Pythagoras theorem as ,

→ AB² = BC² + AC²

→ 4² = 2² + x²

→ 16 = 4 + x²

→ x² = 16-4

→ x² = 12

→ x =√12 = √{ 3 * 2²}

→ x = 2√3

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>

I hope this helps.

3 0
2 years ago
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