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3 years ago

Help! Giving BRAINLIEST!!!!!

Mathematics

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

They did not properly distribute the radicals

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How to find the prime factorization of 65

ddd [48]

5 x 13
65 x 1
This isn't the only factorization, there's also the 65 and 1.

8 0

3 years ago

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A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening

lara [203]

Answer:

Step-by-step explanation:

Because of the nature of the information we are given, we have no choice but to use the equation

$y=a(x-h)^2+k$

and solve for a.

We know by the info that the vertex is (0, 84). We also know that if the vertex is at the origin, and that the base is 42 feet wide, it spans 21 feet to the right of the origin and 21 feet to the left of the origin. That means that we have 2 coordinates from which we need to pick one for our x and y in the equation. I don't like negatives, so I am going to choose the coordinate (21, 0) as x and y. Because this parabola opens upside down, as archways of door openings do, our "a" value better come out algebraically as a negative. Let's see...From the vertex we have that h = 0 and k = 84. So filling in:

$0=a(21-0)^2+84$ and simplifying a bit:

0 = 441a + 84 and

-84 = 441a so

$a=-\frac{84}{441}=-\frac{4}{21}$ Good, a is negative. Your equation is, then:

$y=-\frac{4}{21}x^2+84$

3 0

3 years ago

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An investment account was opened with an initial deposit of 9,600 and earns 7.4% interest compounded continuously, how much will

emmainna [20.7K]

Answer:

10,656

Step-by-step explanation:

I=PRT

I=(9600)(0.074)(15)

Multiply those

I=10,656

3 0

2 years ago

Find sin theta if cos theta is 4/5

Dima020 [189]

Answer:

Step-by-step explanation:

hello :

cos²θ +sin²θ = 1 and cosθ =4/5

(4/5)² + sin²θ = 1 so : sin²θ = 1 - 16/25

sin²θ = 9/25 = (3/5)²

sinθ = 3/5 or sinθ = - 3/5 because : (3/5)²= (- 3/5)²= 9/25

5 0

3 years ago

Statements :

3241004551 [841]

Answer:

" $e^x$ is irrational for every nonzero integer x"

Step-by-step explanation:

The original statement is

" $e^x$ is rational for some nonzero integer x."

The negation is technically:

"It is NOT true that $e^x$ is rational for some nonzero integer x."

So it's expressing that it's false that $e^x$ can be rational for some nonzero integer x.

This just means that $e^x$ is always irrational when x is a nonzero integer.

Which can be worded as

" $e^x$ is irrational for every nonzero integer x"

4 0

3 years ago