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Dmitry_Shevchenko [17]
4 years ago
6

The original amount owed on a loan is known as

Mathematics
1 answer:
beks73 [17]4 years ago
7 0

Answer:

The original amount owned on a loan is known as principal.

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Hence, write as single<br> frachon in its lowest terms.<br> 2/y-1 - 4/y^2-1
sleet_krkn [62]

Answer:

\frac{2}{y+1}

Step-by-step explanation:

Factorise the denominator of the second fraction

y² - 1 = (y - 1)(y + 1) ← difference of squares

To obtain a common denominator

multiply numerator/ denominator of first fraction by (y + 1)

= \frac{2(y+1)}{(y-1)(y+1)} - \frac{4}{(y-1)(y+1)} ← subtract numerators leaving the common denominator

= \frac{2y+2-4}{(y-1)(y+1)}

= \frac{2y-2}{(y-1)(y+1)}

= \frac{2(y-1)}{(y-1)(y+1)} ← cancel common factor (y - 1) on numerator/denominator

= \frac{2}{y+1}

6 0
3 years ago
What is the greatest common factor of 343, 49, and 196? 49 14 7 343 3?
S_A_V [24]
From the prime factorization of 49, we get 7*7. From 196, we get <span>2*2*7*7. From 343, we get 7*7*7. The greatest "overlap" or common factors are 7*7, or 49.</span>

Thus, the greatest common factor is 49.
4 0
3 years ago
Identify the degree of the polynomial 8x^3y^2 – 10xy + 4x^2y^2 + 3.
Anastaziya [24]
When the polynomial has more than one variable you have to sum the exponents of the variables for every monomial. The largest sum is the order of the polynomial.

Here:

momomial   sum of the exponents
8x^3y^2       3 + 2  = 5
-10xy           1 + 1 = 2
4x^2y^2       2 + 2 = 4

Then the degree is 5.
3 0
3 years ago
Read 2 more answers
A recipe shows that the yeast needed for a bread recipe is 2 1/2ounces. Which of the following decimals is equivalent to this nu
UkoKoshka [18]

Answer:

C. 2.3 repeated

Step-by-step explanation:

1/3 doesn't equal a (what you could say is) regular decimal. It repeats because it does not evenly go into 10 or 100

7 0
4 years ago
Read 2 more answers
The population of fish in a pond from 2001 to 2014 is modeled by the function below where t is the years since 2001. using the f
tresset_1 [31]

Given :

The population of fish in a pond from 2001 to 2014 is modeled by the function below where t is the years since 2001.

p(t) = \dfrac{1125}{1+12e^{-0.17t}}    ...1)

To Find :

Find the number of fish is the pond in 2014.

Solution :

Number of years, t = 2014 - 2001 = 13.

Putting value of t in equation 1), we get :

p(t) = \dfrac{1125}{1+12e^{-0.17\times 13}}\\\\p(t) = 485.67

p(t) ≈ 486

Therefore, number of fish in the pond in 2014 is 486.

Hence, this is the required solution.

7 0
3 years ago
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