Answer:
Unit rates are expressed as a quantity of 1, such as 3 feet per second or 6 miles per hour, they are called unit rates.
In the given table shows the number of pictures taken and how much time it took.
For first camera;
Number of pictures (unit rate) per second = 
pictures.
For second Camera:
Number of picture per second = 
pictures.
For third Camera:
Number of picture per second = 
pictures.
The camera that takes picture the fastest is, Second Camera.
(a)
As per the given statement: At Davidson's Bike rentals, it costs $29 to rent a bike for 8 hour.
⇒ unit rate per dollar = 
hours
Therefore, 0.227 hours (nearest to hundredths) of bike use does a customer get per dollar.
(b)
Jessica bought 18 pounds of sugar for $10.
unit rate per dollar = 
therefore, 1.8 pounds of sugar did she get per dollar.
Answer:
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Step-by-step explanation:
Answer:
8x+19=9x+9
Step-by-step explanation:
Simplifying
(8x + 19) = (9x + 9)
Reorder the terms:
(19 + 8x) = (9x + 9)
Remove parenthesis around (19 + 8x)
19 + 8x = (9x + 9)
Reorder the terms:
19 + 8x = (9 + 9x)
Remove parenthesis around (9 + 9x)
19 + 8x = 9 + 9x
Solving
19 + 8x = 9 + 9x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-9x' to each side of the equation.
19 + 8x + -9x = 9 + 9x + -9x
Combine like terms: 8x + -9x = -1x
19 + -1x = 9 + 9x + -9x
Combine like terms: 9x + -9x = 0
19 + -1x = 9 + 0
19 + -1x = 9
Add '-19' to each side of the equation.
19 + -19 + -1x = 9 + -19
Combine like terms: 19 + -19 = 0
0 + -1x = 9 + -19
-1x = 9 + -19
Combine like terms: 9 + -19 = -10
-1x = -10
Divide each side by '-1'.
x = 10
Simplifying
x = 10
25%of44=11 .so 11 frozen yogurt flavours are sugar free
MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
---------------------
(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB
