Question

Which logarithmic equation is equivalent to the exponential equation below?

Answer 1

Answer:

$log_e^{67.21}= a$

Step-by-step explanation:

The equation is ,

$\implies 67.21 = e^a$

• Here e is the Euler's Number . The log which are defined on the base e are called Natural logarithms.

Say if we have a expoteintial equation ,

$\implies a^m = n$

In logarithmic form it is ,

$\implies log_a^n = m$

Similarly our required answer will be ,

$\implies\boxed{ log_e^{67.21}= a }$