Answer:
D 22.5CM
Step-by-step explanation:
Answer:
a) Dependent
b) H0: µd = 0
Ha: µd > 0
c) Stat --> Basic Statistics ----> Paired t. then select samples 1 , 2 to get the required output
d) Not enough data
Step-by-step explanation:
<u>Using values found in MINITAB 19 </u>
a) The samples are dependent and this is because the title of the test is the same ( i.e. A group of students given the LSAT )
<u>b) Appropriate hypothesis</u>
H0: µd = 0
Ha: µd > 0
<u>c) The Minitab procedure to be used to test the hypothesis is </u>
click on Stat --> Basic Statistics ----> Paired t. then select samples 1 , 2 to get the required output
d) Not enough data to create a probability plot
Answer:
Step-by-step explanation:
The two dump intervals have a greatest common factor (GCF) of 3, so their least common multiple (LCM) is ...
(18)(21)/3 = 126 . . . . minutes
This period is 2 hours 6 minutes. The last time both dumped was 1:10, so the next time both will dump is ...
1:10 +2:06 = 3:16 . . . P.M.
and the next time after that is ...
3:16 +2:06 = 5:22 . . . P.M.
<span>The tortoise is runing one mile per hour the entire race.
The hare is runing 3/4 only the first half.
If we multiply by 2 totis =2 miles and hare =1.50 the hare need to run 1/2 or .50 faster to beat the tortis.</span>
