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3 years ago

What is the pattern for 1,4,9,16,25,36,49

Mathematics

2 answers:

siniylev [52]3 years ago

8 0

The pattern would be adding all the odd numbers continuously.

andre [41]3 years ago

4 0

Your adding 5 every time :)

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Convert each improper fraction to a mixed number 5/3= 17/6= 16/5= 9/4= 7/2=

AlexFokin [52]

5/3=1 2/3

17/6=2 5/6

16/5=3 1/5

9/4=2 1/4

7/2=3 1/2

Hope this helps!

7 0

3 years ago

Read 2 more answers

Please answer! Solve for X

Sedbober [7]

Answer:

x = 3

Step-by-step explanation:

We can solve this by using ratios of similar triangles

3 x

------ = ------------

3+9 12

3 x

------ = ------------

12 12

x must equal 3 to keep the ratios the same

4 0

4 years ago

Read 2 more answers

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

6 0

4 years ago

For the set C= {6,8}, determine n(C).

nasty-shy [4]

Step-by-step explanation:

Hey, there!!

C = {6,8}

n(C) means cardinality of set.

We define cardinality of set as the no. of elements present in set.

It contains 2 no. of elements.

so, its cardinality is n(C) is 2.

Hope it helps...

3 0

4 years ago

Gggtfttttttttttttttttttttttt

Marizza181 [45]

Answer:

A) You would move it 2 times B) The Exponent would be 10^2

Step-by-step explanation:

This one's hard to explain..if you want you can message me about it :)

8 0

3 years ago