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3 years ago

There are 3 brownies to share equally with 4 friends. how much brownies will each person get?

Mathematics

2 answers:

agasfer [191]3 years ago

8 0

each person will get 1.333333333333 or 1.3 for short.

Oksana_A [137]3 years ago

8 0

Each person will get 1.3 of a brownie

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Sally has 10 pounds she wants to buy 28 cans of soda which cost 28p each does she have enough money

Vladimir79 [104]

Answer:

Yes, Sally has enough money to buy 28 cans of soda.

Step-by-step explanation:

Yes, because £10 = 1000p

1000p / 28p = 35 cans

35 cans < 28 cans

So Sally has enough money for 28 cans.

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2 years ago

You are responsible to provide tennis balls for a tournament. You know that a ball bounces like new when it is dropped and it bo

nalin [4]

Answer:

arithmetic

Step-by-step explanation:

because it bounced double

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3 years ago

Sandy has 27 roses, 9 daisies, and 36 tulips. She wants to arrange all the flowers in bouquets. Each bouquet has the same number

Ede4ka [16]

9, 9 is the only number that goes into all of the numbers given. there would be 3 bouquets of roses, 1 bouquet of daisies, and 4 bouquets of tulips.

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3 years ago

Read 2 more answers

It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose we are interested i

lidiya [134]

Answer:

Step-by-step explanation:

We are given that 30% of California residents have adequate earthquake supplies.

a) Ramon variable X denotes the number of the california residents that have adequate earthquake insurance

B) x can take value 1 ,2 ,3 ......

C)The distribution of random variable is geometric distribution with parameter p=0.3

The pmf of geometric distribution is

$P(X=x)=0.3(1-0.3)^{x-1} , x=1,2,3...$

D)P(X=1) or P(X=2)=P(X=1)+P(X=2)

P(X=1) or P(X=2)= $0.3(1-0.3)^{1-1}+0.3(1-0.3)^{2-1}=0.51$

$P(X \geq 3)=1-P(X$

$E(X)=\frac{1}{p}$

p is the resident who does not have adequate earthquake supplies.

p = 1-0.3 = 0.7

$E(X)=\frac{1}{0.7}=1.42$

G) $E(X)=\frac{1}{q}=\frac{1}{0.3}=3.33$

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4 years ago

Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.

makkiz [27]

Can't be done without knowing what $f$ is...

But I can tell you that the average value of $f$ is given by

$\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}$

At the very least, we can compute the denominator, which is just the area of $R$ . You have

$\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12$

so the average value will be

$2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy$

4 0

4 years ago