Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):
- For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
- For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
- For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
- For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.
For y=4 draw a horizontal line through the y-axis at point (0,4). Y-axis is the vertical.
For x=-3 draw a vertical line through the x-axis at point (-3,0). X-axis is the horizontal.
Answer:
r = i + j + (-2/3)(3i - j)
Step-by-step explanation:
Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant
if a = i + j ; b = t(3i - j) and r = -i +s(j)
for this to be true all the vector components must be equal
summing i 's
i + 3ti = -i; then t = -2/3
j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3
so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j
I'll write the equation again with the blanks filled in.
1/2 of 2/3 = 1/2 of two thirds = one third
2/3 is read as two thirds.
Half of 2/3 is 1/3, because 1/3+1/3=2/3
Hope this helps!
