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Harman [31]
3 years ago
7

School X and School Y play each other in a competition. School X has six more points than School Y. School X has four times as m

any points as School Y How many points does each school have?
Mathematics
2 answers:
Kipish [7]3 years ago
6 0

Answer:

School X has 8 points and School Y has 2 points

Step-by-step explanation:

From first sentence

X - 6 = Y

From second sentence

X = 4Y

Hence substitute equation 1 into equation 2

4Y - 6 = Y

Y = 2

X = 4 x 2 = 8

QveST [7]3 years ago
6 0

Answer:

School X= 8 points

School Y= 2 points

Step-by-step explanation:

Equation 1:

points of School X can be written as

X= 6+Y ---> eq(1)

Equation 2:

points of School X can be written as

X = 4Y --->eq(2)

In order to find the points of each school, we will equate equation 1 and 2

∴6+Y =4Y

6 = 3Y

Y= 2  putting this value in eq (1)

eq(1)=> X= 6 + 2 =8

Answer: school X has 8 points and school Y has 2 points

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Answer:

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Step-by-step explanation:

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3 years ago
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Rasek [7]
Hello!

To find the side length of a square with the diagonal you use the equation

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3 years ago
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olga2289 [7]
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3 years ago
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Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

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B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

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Step-by-step explanation:

because it is what i think its rright correct me!

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