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garri49 [273]
3 years ago
12

How many related equations does every equation have?

Mathematics
2 answers:
labwork [276]3 years ago
6 0
Its has 2 members 
AX square+ BX square + C AND Y 
charle [14.2K]3 years ago
3 0
The equations have about 2 
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Olegator [25]

Good luck I’m actually looking for answers just like this

6 0
3 years ago
A mad scientist is trying to turn herself into a superhero in her lab at point B. There is an explosion and
yulyashka [42]

Answer:

superheros

Step-by-step explanation:

area of the 8 milrs- 201.06sq miles

area of 10 miles- 314.16sq miles

subtract the 210.06 from 314.16, 104.1

so, 210.06 square miles of heros, 104.1 square miles of villians

7 0
2 years ago
An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
3 years ago
Which of these vectors can be written as a linear combination of vector[-6,-4,7,1] and [-4,-3,2,-1]?
borishaifa [10]

Answer:

Step-by-step explanation:

options?

4 0
3 years ago
What is y-2=-7/4(x-1)?
Debora [2.8K]
The answer is x=15/8
8 0
3 years ago
Read 2 more answers
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