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lutik1710 [3]
3 years ago
15

Solve for g: 4gh+3=-8

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
You cannot calculate this.
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jeff has $25.he spent $10.81,including tax,to buy a new DVD .he needs to set aside $10 to pay for his lunch next week. if peanut
Basile [38]
$ 25.00-$10.81=14.19.
14.19-0.38=13.81.
13.81-10.00=3.81.
He can buy 10 packages of the peanuts.
8 0
3 years ago
Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic
o-na [289]

Answer:

a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

Part a

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0
2 years ago
a farmer sells 7.6 kg of apples and pears at the Farmers Market. Two-fifths of this weight is Apple's, and the rest is pairs. Ho
lutik1710 [3]
1/5 = 20% so... 2/5 = 40%
40% of 7.6 is 3.04
Subtract 3.04 from 7.6, you get 4.56

The farmer sells 4.56 kilograms of pears at the Farmers Market.
7 0
2 years ago
Solve the system of equations.
Sloan [31]

Answer:

b.

( -3, -5)

Step-by-step explanation:

6x + 13 = 2x + 1

6x -2x = 1-13

4x = -12

x = -12/4 = -3

y = 6x + 13

y = 6(-3) +13 = -18+13 = -5

(x, y) = (-3,-5)

7 0
2 years ago
Read 2 more answers
HELP ME PLEASEEEEEEEEE
OLga [1]

Answer:

is it 56 units²? if not sorry

4 0
3 years ago
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