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3 years ago

Solve for x in terms of a,b, and c: ax - 3b =c. . 1: a(c+3b). 2: a (c-3b). 3: c-3/a. 4: c+3b/a

1 answer:

8 0

We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a

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3 years ago

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3 years ago

2. What is the domain and range of the

Lapatulllka [165]

Answer:

domain: x ≥ 0
range: y ≥ 0

Step-by-step explanation:

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2 years ago

The perimeter of a rectangle is 20.2 CM and it's area is 24.4 cm squared what is its length and width

erma4kov [3.2K]

Answer:

Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm

Step-by-step explanation:

Given as :

The perimeter of rectangle = 20.2 cm

The area of rectangle is 24.4 cm

Let the length be L

And width be w

Now Area of rectangle = Length × width

Or, 24.4 = L × W

And Perimeter = 2 (Length + Width ) = 2 (L + W )

Or, 20.2 = 2(L + W )

Or , L + W = 10.1 cm ............ 1

Now, (L - W )² = (L + W)² -4 LW

Or, (L - W )² = ( 10.1)² -4 (24.4)

I.e (L - W )² = 4.41

Or , L - W = 2.1 cm .............. 2

SO , From 1 and 2

( L + W) + (L - W) = 10.1 cm - 2.1 cm

Or, 2L = 8

∴ Length = 4 cm

Again , Width = 4 cm - 2.1 cm = 1.9 cm

Hence Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm Answer

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3 years ago

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Answer:

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