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viktelen [127]
3 years ago
10

The sum of the exterior angles of an octagon is 360 degrees. True False

Mathematics
2 answers:
NeX [460]3 years ago
4 0
The answer is true duh
pishuonlain [190]3 years ago
3 0
The answer is true. 
Hope this helps! :)
You might be interested in
Which number is a solution of a² +4= 6a – 1?<br> 07<br> 6<br> 7<br> 8
LuckyWell [14K]

Answer:

a=1 or a=5

Step-by-step explanation:

a^{2}+4=6a−1

Step 1: Subtract 6a-1 from both sides.

a^{2}+4−(6a−1)=6a−1−(6a−1)

a^{2}−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

a−1=0 or a−5=0

a=1 or a=5

(is it helpful rate me according to that

Thank You:-)

6 0
3 years ago
2,12,8 = 15<br>6, 14,4= 35<br>3,63,7= X​<br>FIND X
Karolina [17]

678899_778886282882

Step-by-step explanation:

hehw

4 0
3 years ago
15% of the students in school eat hot lunch. If 60
morpeh [17]

Answer:

400 students

Step-by-step explanation:

So 15 percent is 60 students

make an equation

0.15x=60

X stands for the total amount fo students and multiply that 0.15 becuase we know ti equals 60 and finding X will solve both problems

that’ll give you 400 students

if you check

400*0.15=60

So its correct

7 0
2 years ago
Using the method of completing the square, put each circle into the form
tatiyna

Answer:

Standard form: (x-\frac{1}{2})^2 + (y-0)^2 = 15

Center: (\frac{1}{2}, 0)

Radius: r =\sqrt{15}

Step-by-step explanation:

The equation of a circle in the standard form is

(x-h)^{2} + (y-k)^{2} = r^{2}

Where the point (h, k) is the center of the circle

To transform this equation 4x^{2} -4x + 4y^{2} - 59 = 0 this equation  in the standard form we use the method of square.

First, we group similar variables

(4x^{2} -4x) + (4y^{2}) - 59 = 0

Divide both sides of equality by 4

(x^{2} -x) + (y^{2}) - 14.75 = 0

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2=  (-\frac{1}{2})^2 = \frac{1}{4}

Now add (\frac{b}{2})^2 on both sides of the equality

(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})

Factor the expression and simplify the independent terms

(x-\frac{1}{2})^2 + (y^{2}) = 15

(x-\frac{1}{2})^2 + (y-0)^2 = 15

Then

h =\frac{1}{2}\\\\k=0

and the center is (\frac{1}{2}, 0)

radius r =\sqrt{15}

3 0
3 years ago
12. The temperature was –3° C last night. It is now 4° C. What was the<br> change in temperature?
aniked [119]

Answer:

7

Step-by-step explanation:

-3 + 3 = 0

0 + 4 = 4

4 + 3 = 7

6 0
3 years ago
Read 2 more answers
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