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2 years ago

9u^2v and which term are like terms?

Mathematics

1 answer:

Oliga [24]2 years ago

5 0

Answer:

$15u^2v$

Step-by-step explanation:

$9u^2v\: and \:15u^2v$ are like terms.

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Use synthetic division to find the result when (x3 - 2x2 - 19x + 20) is divided by (x + 4).

OLga [1]

Answer:

x^2 - 4x - 3 + 28/x+4

Step-by-step explanation:

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2 years ago

What is 25% of 167??????

Alborosie

Answer:

41.75

Step-by-step explanation:

<h2>Hope this helps and have a nice day :)</h2>

6 0

2 years ago

What is the inverse of the function f(x) = 2x + 1?

Tatiana [17]

We have $y=2x+1$ , to find inverse switch y and x then solve for y.

$x=2y+1 \\ x-1=2y \\ y=\frac{x-1}{2}$ .

Hope this helps.

6 0

2 years ago

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$