ANSWER CHOICE C
We have been given two box plots representing attendance at a local movie theater and high school basketball games. WE are asked to choose the correct option about the measure the spread of the data represented by box plots.
Since we know that Standard deviation is not a good measure of spread in highly skewed data. IQR is better measure of spread for highly skewed data.
We can see that box plot representing attendance at movies is right skewed, therefore, mean will be greater than median and SD will not be a good measure of spread.
Box plot representing basket-ball games attendance is left skewed left,therefore, mean will be less than median and SD will not be a good measure of spread.
Our both box plots are highly skewed, therefore, the IQR is the best measurement of spread for games and movies and option C is the correct choice.
The first one
Step-by-step explanation:
the other ones are not statistical
I hope this helps!
Answer:
7 positive integer solutions
Step-by-step explanation:
3(x-5)≤7
Distribute
3x - 15 ≤7
Add 15 to each side
3x-15+15≤7+15
3x≤22
Divide by 3
3x/3 ≤22/3
x≤7 1/3
Positive integer solutions
1,2,3,4,5,6,7 = 7
0 is neither positive nor negative
Step-by-step explanation:
I'll just try to help, I'm not so sure
without outlier
mean = (2+8+5+6+20+7)/6
mean= 48/6
mean= 8
with outlier
mean=(4+2+8+5+6+20+7+9)/8
mean=61/8
mean=7.63
without outlier
median=11/2=5.5
with outlier
median=11/2=5.5
without outlier
mode=0
with outlier
mode=0
without outlier
range=20-2=18
with outlier
range = 18
Answer:
1.1
Step-by-step explanation:
Find the mean of the data:(3+4+5+5+5+6+6+6+7+8)/10 = 5.5Step 2: Find the difference between each data and mean:Difference between 3 and 5.5 is 2.5Difference between 4 and 5.5 is 1.5Difference between 5 and 5.5 is 0.5Difference between 5 and 5.5 is 0.5Difference between 5 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 7 and 5.5 is 1.5Difference between 8 and 5.5 is 2.5Step 3: Add all the differences:2.5+1.5+0.5+0.5+0.5+0.5+0.5+0.5+1.5+2.5 = 11Step 4: Divide it by the number of data:11/10 = 1.1So, the MAD = 1.1
