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a_sh-v [17]
2 years ago
8

A security administrator wants to empty the DNS cache after a suspected attack that may have corrupted the DNS server. The serve

r has been repaired, however it is feared that DNS entries may remain in client computer caches. Which of the following tools can be used to flush the DNS cache on a Windows client?a. NET
b. PING
c. NSLOOKUP
d. IPCONFIG
Computers and Technology
1 answer:
sattari [20]2 years ago
3 0

Answer:

IPCONFIG Pls mark brainliest

Explanation:

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Angelina wants her text to look less crowded on the page, so she decides to decrease the length of the space the text occupies.
ratelena [41]

Answer:

She can go to the Layout tab and then to the Page setup command group to increase the margins of the page.

Explanation:

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The crowd that it has created before automatically gets adjusted and will give a better look.

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3 years ago
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What is an example of a situation in which you might use the append method? In what ways is the append method limited?
Oksanka [162]
If I had an array of the names of people who just walked in the door. I’d append the name of the person who came in next. To update the array.

The append method needs to be looped through to add multiple inputs
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2 years ago
You are adding more features to a linear regression model and hope they will improve your model. If you add an important feature
Ludmilka [50]

Answer:

The answer is "Option A".

Explanation:

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Which topology connects all the computers in a circular pattern
Nimfa-mama [501]
You have to give us the answer options kiddo!
5 0
3 years ago
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Write a C++ program that reads from the standard input and counts the number of times each word is seen. A word is a number of n
Rufina [12.5K]

Answer:

#include <stdio.h>

#include <string.h>

#include <ctype.h>

 

struct detail

{

   char word[20];

   int freq;

};

 

int update(struct detail [], const char [], int);

 

int main()

{

   struct detail s[10];

   char string[100], unit[20], c;

   int i = 0, freq = 0, j = 0, count = 0, num = 0;

 

   for (i = 0; i < 10; i++)

   {

      s[i].freq = 0;

   }

   printf("Enter string: ");

   i = 0;

   do

   {

       fflush(stdin);

       c = getchar();

       string[i++] = c;

 

   } while (c != '\n');

   string[i - 1] = '\0';

   printf("The string entered is: %s\n", string);

   for (i = 0; i < strlen(string); i++)

   {

       while (i < strlen(string) && string[i] != ' ' && isalnum(string[i]))

       {

           unit[j++] = string[i++];

       }

       if (j != 0)

       {

           unit[j] = '\0';

           count = update(s, unit, count);

           j = 0;

       }

   }

 

   printf("*****************\nWord\tFrequency\n*****************\n");

   for (i = 0; i < count; i++)

   {

       printf("%s\t   %d\n", s[i].word, s[i].freq);

       if (s[i].freq > 1)

       {

           num++;

       }

   }

   printf("The number of repeated words are %d.\n", num);

 

   return 0;

}

 

int update(struct detail s[], const char unit[], int count)

{

   int i;

 

   for (i = 0; i < count; i++)

   {

       if (strcmp(s[i].word, unit) == 0)

       {

           s[i].freq++;

 

           return count;

       }

   }

   /*If control reaches here, it means no match found in struct*/

   strcpy(s[count].word, unit);

   s[count].freq++;

 

   /*count represents the number of fields updated in array s*/

   return (count + 1);

}

4 0
3 years ago
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