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lukranit [14]
4 years ago
11

The rate of O2 production by the light reactions varies with the intensity of light because light is required as the energy sour

ce for O2 formation. Thus, lower light levels generally mean a lower rate of O2 production. In addition, lower light levels also affect the rate of CO2 uptake by the Calvin cycle. This is because the Calvin cycle needs the ATP and NADPH produced by the light reactions. In this way, the Calvin cycle depends on the light reactions. But is the inverse true as well? Do the light reactions depend on the Calvin cycle? Suppose that the concentration of CO2 available for the Calvin cycle decreased by 50% (because the stomata closed to conserve water). Which statement correctly describes how O2 production would be affected
Chemistry
1 answer:
Mademuasel [1]4 years ago
8 0

Answer:

Light reaction do not depends on dark reaction because the reaction that occur in presence of light cannot occur in dark . Photolysis, one of most important light reaction cannot take place in dark.

Explanation:

If concentration of carbon dioxide is decreased by 50% then the oxygen production will not be affected because oxygen is produced from the reduction of water.

         

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11. 2073 Set D Q.No. 1 Ammonia molecule has got trigonal
Nikolay [14]

Answer:

See explanation

Explanation:

I know that we usually associate the sp3 hybridization to the tetrahedral shape. This is common in molecules such as CH4. So it may sound somewhat strange that NH3 molecule has an sp3 hybridized nitrogen atom and a trigonal pyramidal geometry.

Let us recall that the central nitrogen atom in NH3 has a lone pair of electrons. These lone pairs causes more repulsion than bond pairs. As a result of the presence of this lone pair, the bond angle in the NH3 molecule is distorted away from the expected 109.7 degrees in tetrahedral geometry and the bonding groups are now arranged in a trigonal pyramidal geometry(with bond angle less than 109.7 degrees) to minimize electron pair repulsions.

5 0
3 years ago
Express in scientific notation. Choose the answer with the proper number of significant figures.
AlekseyPX
5*10^-18 is the answer because in scientific notation the first number has to be between 1 and 10
4 0
3 years ago
Read 2 more answers
If the reaction was reversed and we wanted to produce as much NaN3, in grams, as possible from 30.0 g of N2 and 20.0 g of Na, wh
Valentin [98]

Answer:

N₂

Explanation:

Sodium is a larger molecule with a much higher molecular weight. However, 20g of N₂ would be a smaller amount of molecules than 20g of sodium due to how there are multiple nitrogen molecules.

2/3 * given mass of N₂ = mass of N₃

N₃ (Azide ion) given mass = 20g

Na = 20g

Masses of chemicals are equal

Na = 22.990g/mol

20g/22.990g/mol = 0.8699mol of Na

N₃ = 20g

N₃ = N g/mol x 3

N = 14.007 g/mol

14.007 x 3 = 42.021 g/mol

N₃ = 42.021g/mol

20g/42.021g/mol = 0.4759 mol of N₃

Notice how there are fewer moles of the Azide ion than the Sodium.

0.4759 moles of NaN₃ is produced

combine molecular weights:

42.021 + 22.990 = 65.011 g/mol

multiply by amount of moles of the limiting reactant:

0.4759 mol *65.011 = 30.942 g

Also, here is the balanced equation:

3N₂ + 2Na = 2NaN₃

The results are the same as the balanced equation.

4 0
3 years ago
A 0.35 g sample of Li(s) is placed in an Erlenmeyer flask containing 100 mL of water at 25°C. A balloon is placed over the mouth
Harrizon [31]

Answer:

C- Using a 0.35 g sample of Li(s) cut into smaller pieces will increase the rate of reaction

C- Equal quantities of gas will be produced with potassium K, used instead of Lithium, Li.

Explanation:

<u>First part</u>

When a metal is present in small pieces, the rate of the chemical reaction increases. This is due to small pieces provide more surface area for reaction than huge chunks of Li.

moles of reactant decreases product formation rate also decreases and temperature decreases rate also decreases so remaining option are wrong

<u>Second part </u>

2Li + 2H2O --------------> 2LiOH + H2

2K + 2H2O ---------------> 2KOH + H2  

Hence, both gives same quantity of gas

7 0
3 years ago
The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in
IrinaK [193]

Answer: The value of acid ionization constant K_a for acetic acid is 1.87\times 10^{-5}

Explanation:

CH_3COOH\rightarrow H^+CH_3COO^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.85 M and pH = 2.4

pH=-log[H^+]

[H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}

K_a=?

Putting in the values we get:

K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}

Thus the value of acid ionization constant K_a for acetic acid is 1.87\times 10^{-5}

5 0
3 years ago
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