Explanation:
will dissociate into ions as follows.
![PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)](https://tex.z-dn.net/?f=PbBr_%7B2%7D%28s%29%20%5Crightleftharpoons%20Pb%5E%7B2%2B%7D%28aq%29%20%2B%202Br%5E%7B-%7D%28aq%29)
Hence,
for this reaction will be as follows.
![K_{sp} = [Pb^{2+}][Br^{-}]^{2}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BPb%5E%7B2%2B%7D%5D%5BBr%5E%7B-%7D%5D%5E%7B2%7D)
We take x as the molar solubility of
when we dissolve x moles of solution per liter.
Hence, ionic molarities in the saturated solution will be as follows.
=
+ x
=
+ 2x
So, equilibrium solubility expression will be as follows.
=
Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains
= 0.10 and there will be no lead ions. So,
= 0
So,
will approximately equals to
.
Hence, ![K_{sp} = x[Br^{-}]^{2}_{o}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20x%5BBr%5E%7B-%7D%5D%5E%7B2%7D_%7Bo%7D)
![4.67 \times 10^{-6} = x \times (0.10)^{2}](https://tex.z-dn.net/?f=4.67%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20x%20%5Ctimes%20%280.10%29%5E%7B2%7D)
x =
M
Thus, we can conclude that molar solubility of
is
M.
Hey there!
* Converts 1750 dm³ in liters :
1 dm³ = 1 L so 1750 dm³ = 1750 liters
* Convertes 125,000 Pa in atm :
1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm
* Convertes 127ºC in K :
127 + 273.15 => 400.15 K
R = 0.082 atm.L/mol.K
Finally, it uses an equation of clapeyron :
p * V = n * R * T
1.233 * 1750 = n * 0.082 * 400.15
2157.75 = n * 32.8123
n = 2157.75 / 32.8123
n = 65.76 moles
hope this helps!
Answer:
χsolvent = 1.0000 - 0.1000 = 0.9000
Use Raoult's Law:
Psolution = (χsolvent) (P°solvent)
x = (0.900) (25.756)
x = 23.18 mmHg (to four sig figs)
Answer:
How can we prevent harmful algae blooms?
How do you know if algal blooms are harmful?
Explanation:
I hope this helps