Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship, when temperature is held constant i.e PV = constant. Therefore, P1V1 = P2V2--(i) ( P1 = initial pressure, P2= final pressure, V1= initial volume, V2= final volume). P1=930 torr, P2= 970 torr, V1= 95 ml, V2=?.
Put these values in equation (i),
930 torr x 95 ml = 970 torr x V2. Therefore, V2 = 91.08 ml.
Answer:
it will float back up because it's not dense enough to go down
According to this reaction:
3NO2^- + 8 H^+ + Cr2O7^-2 → 3NO3^- + 2Cr^+3 + 4 H2O
(1) 3 NO2^- → 3NO3^-, The oxidation state of nitrogen converted from +3 to +5
i.e oxidation process, ∴ NO2^- is reducing agent.
(2) Cr2O7^-2 → 2Cr^+3, The oxidation state of Cr converted from +6 to +3
i.e reduction process ∴ Cr2O7^-2 is an Oxidizing agent.
(3) H^+ → H2O, the oxidation state of Hydrogen is still +1, i.e No change (neither)
Answer:
im the only answer your gonna get
Explanation: