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AveGali [126]
3 years ago
8

Type the temperatures in Kelvin) in the left column

Chemistry
2 answers:
docker41 [41]3 years ago
8 0

Answer: the data appear to be ( linear )

The line of best fit is v= 0.003 t+ 0.003

Notice the the value of the v intercept is close to 0 so V and t are ( directly proportional)

Swaggersouls
2 years ago
What about the graph?
ahrayia [7]3 years ago
7 0

Answer:

linear, .003, .003, directly proportional

Explanation:

gl :) <3

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kaheart [24]
200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M

so the answer is c
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What type of reaction is most likely to occur when barium reacts with fluorine? combustion synthesis decomposition single replac
Lana71 [14]
Answer is: synthesis. 
Chemical reaction: Ba + F₂ → BaF₂.
Synthesis is type of reaction where two or more compounds (in this reaction barium and fluorine) react to form one product (in this reaction BaF₂).
BaF₂ - barium fluoride, salt, <span>white cubic crystals, soluble in methanol and ethanol.</span>
8 0
3 years ago
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Atoms of metallic elements tend to...
lara31 [8.8K]

The answer is: lose electrons and form positive ions.

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The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

For example, magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

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3 0
3 years ago
An alpha particle is equivalent to a _____ nucleus.
astra-53 [7]
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6 0
3 years ago
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Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0
3 years ago
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