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3 years ago

Type the temperatures in Kelvin) in the left column

Chemistry

2 answers:

docker41 [41]3 years ago

8 0

Answer: the data appear to be ( linear )

The line of best fit is v= 0.003 t+ 0.003

Notice the the value of the v intercept is close to 0 so V and t are ( directly proportional)

Swaggersouls

2 years ago

What about the graph?

ahrayia [7]3 years ago

7 0

Answer:

linear, .003, .003, directly proportional

Explanation:

gl :) <3

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The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×

Anuta_ua [19.1K]

Answer:

$Kc=~1.49x10^3^4}$

Explanation:

We have the reactions:

A: $N_2_(_g_) + O_2_(_g_) 2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9$

Our target reaction is:

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)$

We have $NO_(_g_)$ as a reactive in the target reaction and $NO_(_g_)$ is present in A reaction but in the products side. So we have to flip reaction A.

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

Then if we add reactions A and B we can obtain the target reaction, so:

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9$

For the final Kc value, we have to keep in mind that when we have to add chemical reactions the total Kc value would be the multiplication of the Kc values in the previous reactions.

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}$

$Kc=~1.49x10^+^3^4}$

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Can Light from the light bulb cause skin cancer? Please explain why or why not? with the evidence? I need an answer till 12:00 o

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2 years ago

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erastovalidia [21]

Explanation:

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3 years ago

Which book has kinetic energy

bekas [8.4K]

Where is the picture

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3 years ago

If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is

kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

Data:

P₁ (initial pressure) = 500 torr
V₁ (initial volume) = 0.5 L
P₂ (final pressure) = 700 torr

Wanted:

V₂ (final volume)

Equation:

P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂

Solution:

V₂ = $\frac{(500 torr)(0.5 L)}{700 torr}$ = 0.3571 L or 0.4 L

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2 years ago