It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.
2 carbons = “eth”
Look at that! Two carbons! It must be “ethene”
<h3>
Answer:</h3>
4.227 × 10^-19 Joules
<h3>
Explanation:</h3>
Energy of a photon of light is calculated by the formula;
E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.
But, f = c/λ
Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.
Given the wavelength is 470 nm or 4.7 × 10^-7 m
Therefore;
E = hc/λ
= (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m
= 4.227 × 10^-19 Joules
Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules
Answer:
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
Explanation:
Nuclei higher than Bi - 92 naturally are radioactive.
In a transmutation reaction, a new element is produced from an existing one due to radioactivity.
Nuclear fission is the radioactive process by which a heavy nucleus spontaneously decays into lighter ones with the release of a large amount of energy.
One example is the transmutation of uranium into thorium;
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
<span>267.21 g/mol
There you go.</span>
Answer:
2C(s, graphite)+ 3H₂(g) + ½O₂(g) ⟶ C₂H₅OH(ℓ)
Explanation:
The thermodynamic standard state of elements and compounds is defined as their most stable state at 25 °C and 1 bar
The elements in ethanol, C₂H₅OH, are C, H, and O.
Their most stable states at standard conditions are C₂H₅OH(ℓ), C(s, graphite), H₂(g), and O₂(g)
The equation for the formation of ethanol from its elements is then
2C(s, graphite) + 3H₂(g) + ½O₂(g) ⟶ C₂H₅OH(ℓ)
